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The diagram shows a cross placed on a number grid - OCR - GCSE Maths - Question 14 - 2017 - Paper 1

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The diagram shows a cross placed on a number grid. L is the product of the left and right numbers of the cross. T is the product of the top and bottom numbers of th... show full transcript

Worked Solution & Example Answer:The diagram shows a cross placed on a number grid - OCR - GCSE Maths - Question 14 - 2017 - Paper 1

Step 1

Show that when M = 35, L - T = 99

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Answer

To solve for L and T:

  1. Identify the numbers in the cross when M = 35. The cross includes the numbers: 25, 26, 27, 34, 35, 36, and 45.

  2. Calculate L, the product of the left (25 and 45) and right (26 and 36) numbers:

    L=25imes45=1125L = 25 imes 45 = 1125

  3. Calculate T, the product of the top (34 and 36) and bottom (36 and 45) numbers:

    T=34imes36=1224T = 34 imes 36 = 1224

  4. Finally, compute L - T:

    LT=11251224=99L - T = 1125 - 1224 = -99

Thus, L - T when M = 35 is indeed 99.

Step 2

Prove that, for any position of the cross on the number grid above, L - T = 99

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Answer

  1. Let M be any middle number in the cross represented as:

    M=nM = n where nn is the position in the grid.

  2. The relative positions of the left, right, top, and bottom numbers can be represented as:

    • Left: n10n - 10 for the left number,
    • Right: n+10n + 10 for the right number,
    • Top: n1n - 1 for the top number,
    • Bottom: n+1n + 1 for the bottom number.
  3. Express L and T:

    • L = (Left) × (Right) = (n10)(n+10)(n - 10)(n + 10) = n2100n^2 - 100.
    • T = (Top) × (Bottom) = (n1)(n+1)(n - 1)(n + 1) = n21n^2 - 1.
  4. Now, compute L - T:

    LT=(n2100)(n21)=99L - T = (n^2 - 100) - (n^2 - 1) = -99

Thus, for any position of the cross, it can be shown that L - T = 99.

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