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5(2(x + 1)) + c(x + d) = 12x - 1 Work out the value of c and the value of d. - OCR - GCSE Maths - Question 11 - 2020 - Paper 3

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Question 11

5(2(x-+-1))-+-c(x-+-d)-=-12x---1--Work-out-the-value-of-c-and-the-value-of-d.-OCR-GCSE Maths-Question 11-2020-Paper 3.png

5(2(x + 1)) + c(x + d) = 12x - 1 Work out the value of c and the value of d.

Worked Solution & Example Answer:5(2(x + 1)) + c(x + d) = 12x - 1 Work out the value of c and the value of d. - OCR - GCSE Maths - Question 11 - 2020 - Paper 3

Step 1

Step 1: Expand the equation

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Answer

Start by expanding the left side of the equation:

5(2(x+1))+c(x+d)=12x15(2(x + 1)) + c(x + d) = 12x - 1

This simplifies to:

10x+5+cx+cd=12x110x + 5 + cx + cd = 12x - 1

Step 2

Step 2: Combine like terms

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Answer

Now, combine the terms involving xx:

(10+c)x+(5+cd)=12x1 (10 + c)x + (5 + cd) = 12x - 1

This gives us a system of equations by equating coefficients.

Step 3

Step 3: Set up the system of equations

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Answer

From the equation above, we can derive two equations:

  1. For the coefficients of xx: 10+c=1210 + c = 12
  2. For the constant terms: 5+cd=15 + cd = -1

Step 4

Step 4: Solve for c

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Answer

From the first equation, solve for cc:

c=1210=2c = 12 - 10 = 2

Step 5

Step 5: Solve for d

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Answer

Substituting c=2c = 2 into the second equation:

5+2d=15 + 2d = -1

Now, solve for dd:

2d=15=6d=62=32d = -1 - 5 = -6 \\ d = \frac{-6}{2} = -3

Step 6

Final values

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Answer

Thus, the values are:

  • c=2c = 2
  • d=3d = -3

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