The dimensions, in centimetres, of this rectangle are shown as algebraic expressions - OCR - GCSE Maths - Question 9 - 2018 - Paper 1

Next, we utilize the expression for the width:

Using the equation from part one:

• 5x - y - 8

We can set up the following equation:

$3x + y - 4 = 5x - y - 8$

Rearranging yields:

$3x + y + y = 5x - 8 + 4$

This simplifies to:

$2y - 2x = -4$

Divide through by 2:

$y - x = -2$

Now we have two equations to solve:

1. $x + 7y = 1$
2. $y - x = -2$

From the second equation, we can express y in terms of x:

$y = x - 2$

Substituting this into the first equation provides:

$x + 7(x - 2) = 1$

This leads to:

$8x - 14 = 1$

So:

ightarrow x = rac{15}{8}$$ Substituting x back into the equation for y gives: $$y = rac{15}{8} - 2 = -rac{1}{8}$$ Thus, the dimensions of the rectangle are determined.