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Solve by factorisation - OCR - GCSE Maths - Question 16 - 2018 - Paper 4

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Question 16

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Solve by factorisation. $$2x^2 - 19x - 33 = 0$$

Worked Solution & Example Answer:Solve by factorisation - OCR - GCSE Maths - Question 16 - 2018 - Paper 4

Step 1

Step 1: Factor the Quadratic Equation

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Answer

To solve the equation (2x^2 - 19x - 33 = 0) by factorisation, we start by finding two numbers that multiply to (2 \times -33 = -66) and add to (-19). The numbers (-22) and (+3) satisfy these conditions.

Now we can rewrite the middle term:

2x222x+3x33=02x^2 - 22x + 3x - 33 = 0

Next, we group the terms:

2x(x11)+3(x11)=02x(x - 11) + 3(x - 11) = 0

Step 2

Step 2: Solve for x

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Answer

Now we factor out ((x - 11)

(2x+3)(x11)=0(2x + 3)(x - 11) = 0

Setting each factor to zero gives:

  1. (2x + 3 = 0)

    • This simplifies to (2x = -3) hence (x = -\frac{3}{2})
  2. (x - 11 = 0)

    • This simplifies to (x = 11)

Thus, the solutions are: [ x = -\frac{3}{2} \text{ or } x = 11 ]

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