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iodine is required for a healthy diet - Scottish Highers Chemistry - Question 11 - 2018

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iodine is required for a healthy diet. Food grown in certain parts of the world is low in iodine. To prevent iodine deficiency in people’s diets, table salt can be ‘... show full transcript

Worked Solution & Example Answer:iodine is required for a healthy diet - Scottish Highers Chemistry - Question 11 - 2018

Step 1

Describe a procedure to accurately weigh out a 50.0 g sample of iodised table salt.

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Answer

To accurately weigh a 50.0 g sample of iodised table salt, use a balance. First, ensure the balance is calibrated and set to zero (tare) with the weighing boat or paper. Gradually add iodised salt until the balance reads exactly 50.0 g. Take care to avoid adding excess salt, and confirm the weight before removing the sample from the balance.

Step 2

Write the ion-electron equation for the oxidation reaction.

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Answer

The ion-electron equation for the oxidation reaction involving iodide ions is:

ightarrow I_2(aq) + 2e^-$$

Step 3

Calculate the average volume, in cm³, of sodium thiosulfate solution that should be used to determine the number of moles of iodine released.

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Answer

To calculate the average volume of sodium thiosulfate solution used:

  1. Add the volumes of all samples:

    10.0extcm3+9.4extcm3+9.6extcm3=29.0extcm310.0 ext{ cm}^3 + 9.4 ext{ cm}^3 + 9.6 ext{ cm}^3 = 29.0 ext{ cm}^3

  2. Divide by the number of samples (3):

    ext{Average Volume} = rac{29.0 ext{ cm}^3}{3} = 9.67 ext{ cm}^3

Step 4

Calculate the number of moles of iodine released from 50 cm³ of the standard salt solution.

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Answer

To calculate the number of moles of iodine released:

  1. Use the average volume of sodium thiosulfate from part (c)(i) which is 9.67 cm³:
  2. Calculate moles of sodium thiosulfate:

Using the concentration of sodium thiosulfate (0.0010 mol/dm³):

extMoles=extConcentrationimesextVolume extMoles=0.0010extmol/dm3imes0.00967extdm3=9.67imes106extmoles ext{Moles} = ext{Concentration} imes ext{Volume}\ ext{Moles} = 0.0010 ext{ mol/dm}^3 imes 0.00967 ext{ dm}^3 = 9.67 imes 10^{-6} ext{ moles}

  1. According to the reaction, the mole ratio of I₂ to Na₂S₂O₃ is 1:2, thus:

    ext{Moles of I₂} = rac{9.67 imes 10^{-6}}{2} = 4.84 imes 10^{-6} ext{ moles}

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