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Fireworks contain a range of chemicals including a fuel, oxidising agents and metal salts - Scottish Highers Chemistry - Question 2 - 2022

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Fireworks contain a range of chemicals including a fuel, oxidising agents and metal salts. (a) One oxidising agent used in fireworks is potassium perchlorate, KClO₄... show full transcript

Worked Solution & Example Answer:Fireworks contain a range of chemicals including a fuel, oxidising agents and metal salts - Scottish Highers Chemistry - Question 2 - 2022

Step 1

Balance this equation.

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Answer

The balanced equation for the reaction is: 3KClO4+8Al3KCl+4Al2O33KClO₄ + 8Al → 3KCl + 4Al₂O₃

Step 2

Calculate the volume of oxygen produced, in litres, when 4.6 g of potassium chlorate decomposes.

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Answer

First, calculate the number of moles of KClO₃:

Moles of KClO3=4.6 g122.6 g/mol=0.03752 moles\text{Moles of } KClO₃ = \frac{4.6 \text{ g}}{122.6 \text{ g/mol}} = 0.03752 \text{ moles}

From the balanced equation, 2 moles of KClO₃ produce 3 moles of O₂:

Moles of O2=0.03752 moles KClO₃×3extmolesO22extmolesKClO3=0.05628 moles O₂\text{Moles of } O₂ = 0.03752 \text{ moles KClO₃} \times \frac{3 ext{ moles O₂}}{2 ext{ moles KClO₃}} = 0.05628 \text{ moles O₂}

Next, calculate the volume of O₂ produced:

Volume of O2=0.05628 moles×24 L/mole=1.3524 L\text{Volume of } O₂ = 0.05628 \text{ moles} \times 24 \text{ L/mole} = 1.3524 \text{ L}

Thus, the volume of oxygen produced is approximately 1.35 litres.

Step 3

State the effect of adding a catalyst on the enthalpy change for this reaction.

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Answer

Adding a catalyst does not affect the enthalpy change for the reaction; it only speeds up the reaction rate without changing the overall energy change.

Step 4

Calculate the energy, in kJ, released per mole of potassium perchlorate.

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Answer

First, calculate the number of moles of potassium perchlorate:

Moles of KClO4=5.5 g138.6 g/mol=0.0397 moles\text{Moles of } KClO₄ = \frac{5.5 \text{ g}}{138.6 \text{ g/mol}} = 0.0397 \text{ moles}

Next, calculate the energy released per mole:

Energy per mole=103 kJ0.0397 moles2595.6 kJ/mol\text{Energy per mole} = \frac{103 \text{ kJ}}{0.0397 \text{ moles}} \approx 2595.6 \text{ kJ/mol}

Step 5

Explain fully why increasing temperature increases the rate of a chemical reaction.

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Answer

Increasing temperature increases the rate of a chemical reaction due to a rise in the energy of the particles involved. This leads to:

  1. An increased number of particles having energy equal to or greater than the activation energy, thus facilitating more successful collisions.
  2. A greater frequency of collisions between reactants, increasing the likelihood of reaction. As a result, the overall rate of reaction increases.

Step 6

Suggest the metal responsible for peak B on the spectrum.

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Answer

The metal responsible for peak B on the spectrum is likely Sodium, which emits a characteristic yellow light.

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