Photo AI

Reactions involving iodine are commonly used to investigate rates of reaction - Scottish Highers Chemistry - Question 2 - 2017

Question icon

Question 2

Reactions-involving-iodine-are-commonly-used-to-investigate-rates-of-reaction-Scottish Highers Chemistry-Question 2-2017.png

Reactions involving iodine are commonly used to investigate rates of reaction. (a) One reaction involves hydrogen and iodine reacting together to form hydrogen iodi... show full transcript

Worked Solution & Example Answer:Reactions involving iodine are commonly used to investigate rates of reaction - Scottish Highers Chemistry - Question 2 - 2017

Step 1

Explain, using bond enthalpies, which bond is more likely to break first during this reaction.

96%

114 rated

Answer

In the reaction between hydrogen ( ext{H}_2 ext{)} and iodine ( ext{I}_2 ext{)}, the bond that is more likely to break first is the I–I bond due to its lower bond enthalpy compared to the H–H bond. The bond enthalpy of H–H is approximately 436 kJ mol⁻¹, while that of I–I is about 151 kJ mol⁻¹. Therefore, the weaker I–I bond will break more easily.

Step 2

Add a second curve to the graph to show the distribution of kinetic energies at 400 °C.

99%

104 rated

Answer

The second curve should peak further to the right of the original curve on the graph indicating an increase in the distribution of kinetic energies at a higher temperature (400 °C). This shift reflects the higher average kinetic energy of the reactant molecules due to increased thermal energy.

Step 3

State the effect of increasing temperature on the position of equilibrium.

96%

101 rated

Answer

Increasing the temperature shifts the equilibrium position to the left (toward the reactants) for the exothermic reaction.

Step 4

State why changing the pressure has no effect on this equilibrium reaction.

98%

120 rated

Answer

Changing the pressure has no effect on this equilibrium reaction because the number of moles of gaseous reactants and products remains equal (2 moles of H₂ and I₂ yield 2 moles of HI).

Step 5

State the term for the unstable arrangement of atoms.

97%

117 rated

Answer

The term for the unstable arrangement of atoms is 'activated complex'.

Step 6

Calculate the enthalpy change, in kJ, for the forward reaction.

97%

121 rated

Answer

The enthalpy change for the forward reaction can be calculated as the difference between the potential energies of the reactants and products. Based on the diagram, the enthalpy change is:

extEnthalpychange=Ea(forward)Ea(backward)=173.2extkJ182.1extkJ=9.6extkJ ext{Enthalpy change} = E_a (forward) - E_a (backward) = 173.2 ext{ kJ} - 182.1 ext{ kJ} = -9.6 ext{ kJ}

Step 7

State the effect that platinum would have on the activation energy for the reaction.

96%

114 rated

Answer

The presence of platinum as a catalyst would lower the activation energy for the reaction, making it proceed more quickly.

Step 8

Suggest a reason why the beaker should be dry.

99%

104 rated

Answer

The beaker must be dry to ensure that the concentrations of the reactants are not diluted by any water present, which could affect the reaction rate.

Step 9

Calculate the time, in seconds, for the reaction in experiment 3.

96%

101 rated

Answer

The time for the reaction in experiment 3 is given as 123 seconds.

Step 10

Explain why decreasing the concentration of iodide ions lowers the reaction rate.

98%

120 rated

Answer

Decreasing the concentration of iodide ions lowers the reaction rate because it reduces the number of successful collisions between reactant molecules. Lower concentration leads to fewer moles of reactant available, which decreases the frequency of collisions needed for the reaction to occur.

Join the Scottish Highers students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;