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8. Fizzy drinks are made by adding carbon dioxide gas, preservative, colouring and flavouring to water - Scottish Highers Chemistry - Question 8 - 2022

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8. Fizzy drinks are made by adding carbon dioxide gas, preservative, colouring and flavouring to water. (a) Carbon dioxide for fizzy drinks can be produced using th... show full transcript

Worked Solution & Example Answer:8. Fizzy drinks are made by adding carbon dioxide gas, preservative, colouring and flavouring to water - Scottish Highers Chemistry - Question 8 - 2022

Step 1

A catalyst for this reaction is copper(II) oxide.

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Answer

  1. Rate of forward reaction: Increases because the catalyst lowers the activation energy, facilitating more successful collisions.
  2. Rate of reverse reaction: Increases for the same reason, as it lowers the energy barrier in both directions.
  3. Position of equilibrium: No effect, as catalysts do not alter the concentrations of reactants or products at equilibrium.

Step 2

Draw a line on the axes below to show how the yield of carbon dioxide would vary with increasing temperature.

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Answer

The graph should show a decrease in yield as temperature increases because the reaction is exothermic. As temperature rises, the equilibrium shifts to favor the endothermic direction, decreasing the amount of carbon dioxide produced.

Step 3

Show, by calculation, that sorbic acid is the limiting reactant.

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Answer

  1. Calculate moles of sorbic acid:
    • Molar mass = 112 g/mol
    • Moles = mass / molar mass = 7 g / 112 g/mol = 0.0625 moles.
  2. Calculate moles of potassium hydroxide:
    • Concentration = 0.5 mol/dm³, Volume = 250 cm³ = 0.250 dm³.
    • Moles = concentration × volume = 0.5 mol/dm³ × 0.250 dm³ = 0.125 moles.
  3. Since the reaction consumes a 1:1 ratio of sorbic acid to potassium hydroxide, and we have 0.0625 moles of sorbic acid, it is the limiting reactant.

Step 4

Calculate the number of moles of ammonium ferric citrate required to make 330 cm³ of this fizzy drink.

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Answer

  1. Find the amount of ammonium ferric citrate in grams:
    • 0.002% in 330 cm³ = 0.002/100 × 330 g = 0.0066 g.
  2. Calculate moles:
    • Moles = mass / molar mass = 0.0066 g / 261.8 g/mol ≈ 0.0000252 moles.

Step 5

State one property of an essential oil.

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Answer

Essential oils are volatile and usually aromatic, meaning they can easily evaporate and contribute to fragrance.

Step 6

Name the type of compound formed when isoprene units join together.

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Answer

The compound formed is a diene or polyene, specifically a terpenoid due to its structure.

Step 7

Draw a structural formula for isoprene.

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Answer

The structural formula for isoprene is:

  H  H
   \/ 
  C  =  C
  |      
  H  C  -  C  -  H
  |       
  H      H  

Step 8

State the number of isoprene units in a zingiberene molecule.

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Answer

Zingiberene consists of 3 isoprene units.

Step 9

Name product X.

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Answer

Product X is shogaol.

Step 10

Name two functional groups present in gingerol and shogaol that are not present in zingiberene.

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Answer

  1. Hydroxyl group (-OH)
  2. Carbonyl group (C=O)

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