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A mixture of magnesium bromide and magnesium sulfate is known to contain 3 moles of magnesium ions and 4 moles of bromide ions - Scottish Highers Chemistry - Question 6 - 2022

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A mixture of magnesium bromide and magnesium sulfate is known to contain 3 moles of magnesium ions and 4 moles of bromide ions. How many moles of sulfate ions are p... show full transcript

Worked Solution & Example Answer:A mixture of magnesium bromide and magnesium sulfate is known to contain 3 moles of magnesium ions and 4 moles of bromide ions - Scottish Highers Chemistry - Question 6 - 2022

Step 1

Determine the composition of magnesium compounds

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Answer

Magnesium bromide ( ext{MgBr}_2) contains 1 magnesium ion and 2 bromide ions per formula unit. Thus, the presence of 4 moles of bromide ions indicates that the number of moles of magnesium bromide present is:

extMolesofMgBr2=4 moles of Br2=2 moles of MgBr2 ext{Moles of MgBr}_2 = \frac{4\text{ moles of Br}^-}{2} = 2 \text{ moles of MgBr}_2

Step 2

Calculate moles of magnesium ions from magnesium sulfate

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Answer

To find the number of moles of magnesium ions, we note that magnesium sulfate ( ext{MgSO}_4) contains 1 magnesium ion per formula unit. Given that there are 3 moles of magnesium ions total, the moles of magnesium sulfate can be calculated as:

extMolesofMgSO4=32=1 mole of MgSO4 ext{Moles of MgSO}_4 = 3 - 2 = 1 \text{ mole of MgSO}_4

Step 3

Determine the moles of sulfate ions

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Since each mole of magnesium sulfate produces one mole of sulfate ions, the moles of sulfate ions present are:

Moles of sulfate ions=1 mole of MgSO4=1 mole of SO42\text{Moles of sulfate ions} = 1 \text{ mole of MgSO}_4 = 1 \text{ mole of SO}_4^{2-}

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