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The following reactions take place when nitric acid is added to zinc - Scottish Highers Chemistry - Question 4 - 2019

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The following reactions take place when nitric acid is added to zinc. $$NO_3^{-} (aq) + 4H^{+}(aq) + 3e^{-} \rightarrow NO(g) + 2H_2O(l)$$ $$Zn(s) \rightarrow Zn^{... show full transcript

Worked Solution & Example Answer:The following reactions take place when nitric acid is added to zinc - Scottish Highers Chemistry - Question 4 - 2019

Step 1

Identify the half-reactions

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Answer

The relevant half-reactions from the provided information are:

  1. Reduction of nitrate ion: NO3+4H++3eNO+2H2ONO_3^{-} + 4H^{+} + 3e^{-} \rightarrow NO + 2H_2O

  2. Oxidation of zinc: ZnZn2++2eZn \rightarrow Zn^{2+} + 2e^{-}

Step 2

Balance the electrons

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Answer

To find the relationship between the reactants, we need to balance the electrons. The reduction reaction consumes 3 electrons while the oxidation reaction produces 2 electrons.

To balance these, we can find the least common multiple (LCM) of 2 and 3, which is 6.

Thus, we multiply the half-reactions as follows:

  • The reduction reaction is multiplied by 2, giving 6 electrons: 2NO3+8H++6e2NO+4H2O2NO_3^{-} + 8H^{+} + 6e^{-} \rightarrow 2NO + 4H_2O
  • The oxidation reaction is multiplied by 3, also giving 6 electrons: 3Zn3Zn2++6e3Zn \rightarrow 3Zn^{2+} + 6e^{-}

Step 3

Determine moles of Zn oxidized per mole of NO3-

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Answer

From the balanced half-reactions, 2 moles of nitrate ions oxidize 3 moles of zinc. Therefore, 1 mole of nitrate ion would oxidize:

32=1.5  moles  of  Zn\frac{3}{2} = 1.5 \; moles \; of \; Zn

Hence, the answer is 1.5.

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