A mixture of sodium chloride and sodium sulfate is known to contain 0.6 mol of chloride ions and 0.2 mol of sulfate ions - Scottish Highers Chemistry - Question 12 - 2018
Question 12
A mixture of sodium chloride and sodium sulfate is known to contain 0.6 mol of chloride ions and 0.2 mol of sulfate ions.
How many moles of sodium ions are present?
Worked Solution & Example Answer:A mixture of sodium chloride and sodium sulfate is known to contain 0.6 mol of chloride ions and 0.2 mol of sulfate ions - Scottish Highers Chemistry - Question 12 - 2018
Step 1
Determine moles of sodium ions from chloride ions
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Answer
Sodium chloride (NaCl) dissociates into Na extsuperscript{+} and Cl extsuperscript{−}. Since there are 0.6 mol of chloride ions, there are also 0.6 mol of sodium ions from NaCl.
Step 2
Determine moles of sodium ions from sulfate ions
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Answer
Sodium sulfate (Na extsubscript{2}SO extsubscript{4}) dissociates into 2 Na extsuperscript{+} and SO extsubscript{4} extsuperscript{2−}. With 0.2 mol of sulfate ions, we get 0.4 mol of sodium ions (2 × 0.2).
Step 3
Calculate total moles of sodium ions
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Answer
Total moles of sodium ions = moles from NaCl + moles from Na extsubscript{2}SO extsubscript{4} = 0.6 + 0.4 = 1.0 mol.
Step 4
Final answer
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Answer
Therefore, there are 1.0 moles of sodium ions present.
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