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Soft drinks contain a variety of sugars - Scottish Highers Chemistry - Question 11 - 2016

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Soft drinks contain a variety of sugars. A student investigated the sugar content of a soft drink. (a) The density of the soft drink can be used to estimate its tot... show full transcript

Worked Solution & Example Answer:Soft drinks contain a variety of sugars - Scottish Highers Chemistry - Question 11 - 2016

Step 1

Draw a diagram of a volumetric flask.

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Answer

The diagram should represent a volumetric flask with a long, narrow neck and a flat base. The flask should be labeled to indicate the neck and the base. It must show a single graduation mark for accurate measurement.

Step 2

Describe fully a method that the student could have used to accurately measure the mass of 10.0 cm³ of each sucrose solution.

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Answer

To measure the mass of 10.0 cm³ of each sucrose solution accurately, the student could use a pipette to dispense the solution into a weighing boat or container. First, tare the balance with the empty container. Then, use the pipette to add 10.0 cm³ of the sucrose solution to the container. Finally, measure the mass of the container with the solution and subtract the mass of the empty container to find the mass of the sucrose solution.

Step 3

Draw a line graph using the student's results.

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On graph paper, plot the % concentration of sucrose solution on the x-axis and the density of sucrose solution on the y-axis. Use appropriate scales and ensure all data points from the table are plotted correctly. Draw a best fit line through the points to show the relationship. All points should be within tolerance, with axes labeled.

Step 4

Suggest a reason why the soft drink needed to be flat before its density was determined.

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The soft drink needed to be flat to ensure that no carbon dioxide gas was dissolved in the liquid. If gas is present, it can affect the measurement of density by increasing the volume and thereby giving an inaccurate density reading.

Step 5

Using the equation, calculate the % concentration of sugars present in the soft drink.

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Using the equation provided, rearrange it to find the % concentration of sugars in the soft drink:

ext{density} = (0.0204 \times \text{% concentration}) + 1.00

Substituting in the soft drink density (1.07 g cm⁻³):

1.07 = (0.0204 \times \text{% concentration}) + 1.00

Solving for % concentration:

0.07 = 0.0204 \times \text{% concentration}

\text{% concentration} = \frac{0.07}{0.0204} \approx 3.43 ext{%}

Step 6

Calculate the total mass of sugar present, in grams, in a 330 cm³ can of this soft drink.

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Answer

Given that the soft drink contains 10⁻⁶ grams of sugar in 100 cm³, calculate the total mass in a 330 cm³ can:

Total mass=(106 g100 cm3)×330 cm3=3.30×106 g\text{Total mass} = \left( \frac{10^{-6} \text{ g}}{100 \text{ cm}^3} \right) \times 330 \text{ cm}^3 = 3.30 \times 10^{-6} \text{ g}

Step 7

Draw this functional group.

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Answer

The aldehyde functional group is represented as -CHO, where there is a carbon atom double-bonded to an oxygen (carbonyl) and single-bonded to a hydrogen atom.

Step 8

Write the ion-electron equation for the oxidation reaction.

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Answer

The ion-electron equation for the oxidation of the reducing sugar by Fehling's solution is:

2Cu2++reducing sugar2Cu++oxidized form of reducing sugar2\text{Cu}^{2+} + \text{reducing sugar} \rightarrow 2\text{Cu}^+ + \text{oxidized form of reducing sugar}

Step 9

State the colour change that would be observed when reducing sugars are reacted with Fehling's solution.

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The reducing sugars would change the color of Fehling’s solution from blue to brick-red or orange when reacted.

Step 10

Calculate the concentration, in mol dm⁻³, of reducing sugars present in the diluted sample of the soft drink.

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Answer

Using the titration data:

  • The volume of Fehling's solution used is 19.8 cm³, which is 0.0198 dm³.
  • The concentration of Cu²⁺ in Fehling's solution is 0.0250 mol dm⁻³.

Using the stoichiometric relationship:

Moles of Cu2+=0.0198 dm3×0.0250 mol dm3=0.000495extmol\text{Moles of } Cu^{2+} = 0.0198 \text{ dm}^3 \times 0.0250 \text{ mol dm}^{-3} = 0.000495 ext{ mol}

Given the stoichiometry (1:1) between Cu²⁺ and reducing sugar:

The concentration of reducing sugars in the original sample is:

Cs=0.000495 mol0.0250 dm3=0.0198 mol dm3C_s = \frac{0.000495 \text{ mol}}{0.0250 \text{ dm}^3} = 0.0198 \text{ mol dm}^{-3}

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