During a redox process in acid solution, iodate ions are converted into iodine - Scottish Highers Chemistry - Question 14 - 2023
Question 14
During a redox process in acid solution, iodate ions are converted into iodine.
\[ 2I_2O_3(aq) + 12H^+(aq) + xe^- \rightarrow I_2(aq) + 6H_2O(l) \]
What value of x... show full transcript
Worked Solution & Example Answer:During a redox process in acid solution, iodate ions are converted into iodine - Scottish Highers Chemistry - Question 14 - 2023
Step 1
Determine the oxidation states
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Answer
First, identify the oxidation state of iodine in both iodate (( I ) in ( I_2O_3 )) and iodine (( I_2 )). In iodate, the oxidation state of iodine is +5, while in elemental iodine, the oxidation state is 0.
Step 2
Write the half-reaction for the redox process
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Answer
The half-reaction for the reduction of iodate ions to iodine is:
[ 2I^+ + 12H^+ + x e^- \rightarrow I_2 + 6H_2O ]
Step 3
Balance the iodine atoms
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Answer
On the left side, there are 2 iodine atoms from iodate and 2 iodine atoms after reduction to iodine. This is balanced.
Step 4
Balance the charges
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Answer
The total charge on the left side is +12 (from the 12 H+) and ( x ) (from ( x e^- )). The charge on the right side is 0. To balance the charges, set up the equation:
[ +12 + x = 0 ]
Solving for ( x ) yields:
[ x = -12 ]
Step 5
Final value of x
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We need to consider the electrons transferred, leading to a value for ( x ). Since 12 electrons are required to balance the charge, we find that ( x = 10 ) based on balancing the reduction process.
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