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Methyl benzoate is commonly added to perfumes as it has a pleasant smell - Scottish Highers Chemistry - Question 3 - 2018

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Methyl benzoate is commonly added to perfumes as it has a pleasant smell. A student carries out a reaction to produce methyl benzoate using the following apparatus. ... show full transcript

Worked Solution & Example Answer:Methyl benzoate is commonly added to perfumes as it has a pleasant smell - Scottish Highers Chemistry - Question 3 - 2018

Step 1

Describe a safe method of heating a flammable mixture.

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Answer

A safe method to heat a flammable mixture is to use a heating mantle or a hot plate. Both of these methods provide a controlled heat source without the risks associated with an open flame.

Step 2

Suggest a reason why there is a small test tube filled with cold water in the neck of the tube containing the reaction mixture.

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Answer

The small test tube filled with cold water acts as a condenser to prevent the escape of volatile or gaseous reactants or products during the reaction. This helps maintain the reaction mixture and improves yield.

Step 3

Name product X.

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Answer

Product X is water (H₂O).

Step 4

Explain why benzoic acid is the limiting reactant.

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Answer

To determine the limiting reactant, we first calculate the number of moles:

For benzoic acid: Moles = mass (g) / molar mass (g/mol) = 5.0 g / 122 g/mol = 0.041 moles

For methanol: Moles = mass (g) / molar mass (g/mol) = 2.5 g / 32 g/mol = 0.078 moles

The balanced equation shows that 1 mole of benzoic acid reacts with 1 mole of methanol. Therefore, to fully react with 5 g of benzoic acid, it would require 5 g of benzoic acid to react with 0.041 moles of methanol. Since we have more than enough methanol (0.078 moles available), benzoic acid is the limiting reactant.

Step 5

Calculate the cost, in £, of the benzoic acid needed to make 100 g of methyl benzoate using the student's method.

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Answer

First, calculate how much benzoic acid is needed to produce 100 g of methyl benzoate:

From the reaction, the molar ratio of benzoic acid to methyl benzoate is 1:1. Therefore, producing 100 g of methyl benzoate requires 5 g of benzoic acid:

Cost for 500g of benzoic acid = £39.80 Cost for 1g = £39.80 / 500 = £0.0796 Cost for 5g = 5 * £0.0796 = £0.398

Thus, the total cost for the benzoic acid needed to make 100 g of methyl benzoate is approximately £0.398.

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