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The diagram below shows the graph with equation $y = f(x)$, where $f(x) = k(x-a)(x-b)$ - Scottish Highers Maths - Question 15 - 2016

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Question 15

The-diagram-below-shows-the-graph-with-equation-$y-=-f(x)$,-where-$f(x)-=-k(x-a)(x-b)$-Scottish Highers Maths-Question 15-2016.png

The diagram below shows the graph with equation $y = f(x)$, where $f(x) = k(x-a)(x-b)$. (a) Find the values of $a$, $b$ and $k$. (b) For the function $g(y) = f(x)... show full transcript

Worked Solution & Example Answer:The diagram below shows the graph with equation $y = f(x)$, where $f(x) = k(x-a)(x-b)$ - Scottish Highers Maths - Question 15 - 2016

Step 1

Find the values of $a$

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Answer

From the graph, the roots are located at x=5x = -5 and x=4x = 4. Based on the positive root structure of the equation, we assign:

a=5a = -5

Step 2

Find the values of $b$

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Answer

Thus, we also identify:

b=4b = 4

Step 3

calculate $k$

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Answer

To find the value of kk, we use the known point (1,9)(1, 9). Substituting into the equation:

f(1)=k(1a)(1b)f(1) = k(1 - a)(1 - b) We calculate:

f(1)=k(1(5))(14)f(1) = k(1 - (-5))(1 - 4) 9=k(6)(3)9 = k(6)(-3) 9=18k9 = -18k

Solving for kk yields:

k = - rac{1}{2}

Step 4

For the function $g(y) = f(x) - d$, determine the range of values of $d$

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Answer

For g(y)g(y) to have exactly one real root, dd must be equal to the maximum value of f(x)f(x). From the graph, the maximum value of f(x)f(x) occurs at the vertex, which is at (1,9)(1, 9):

Thus, the only value for dd that allows g(y)g(y) to have exactly one real root is:

d<9d < 9

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