Photo AI

A and B are the points (-7, 2) and (5, a) - Scottish Highers Maths - Question 11 - 2017

Question icon

Question 11

A-and-B-are-the-points-(-7,-2)-and-(5,-a)-Scottish Highers Maths-Question 11-2017.png

A and B are the points (-7, 2) and (5, a). AB is parallel to the line with equation 3y - 2x = 4. Determine the value of a.

Worked Solution & Example Answer:A and B are the points (-7, 2) and (5, a) - Scottish Highers Maths - Question 11 - 2017

Step 1

Determine the gradient of the given line

96%

114 rated

Answer

To find the gradient of the line represented by the equation (3y - 2x = 4), we first rearrange it into slope-intercept form ((y = mx + b)):

  1. Rearranging gives: (3y = 2x + 4)
  2. Dividing through by 3 results in: (y = \frac{2}{3}x + \frac{4}{3})

Thus, the gradient (m) of the given line is (m = \frac{2}{3}.

Step 2

Determine the other gradient

99%

104 rated

Answer

Since line AB is parallel to the line from the previous step, its gradient must also be (m_{AB} = \frac{2}{3}.

Step 3

Find a

96%

101 rated

Answer

The points A and B have coordinates A(-7, 2) and B(5, a). We use the formula for the gradient of a line through two points, which is given by:

(m_{AB} = \frac{y_2 - y_1}{x_2 - x_1})
Substituting the known values gives us:
(\frac{2 - a}{5 - (-7)} = \frac{2}{3})
This simplifies to (\frac{2 - a}{12} = \frac{2}{3}).
Cross-multiplying yields:
(3(2 - a) = 24)
(6 - 3a = 24)
(-3a = 24 - 6)
(-3a = 18)
Thus, (a = -6.

Join the Scottish Highers students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;