Photo AI

A student sets up an experiment to investigate the interaction between two trolleys on a smooth, horizontal track - Scottish Highers Physics - Question 3 - 2022

Question icon

Question 3

A-student-sets-up-an-experiment-to-investigate-the-interaction-between-two-trolleys-on-a-smooth,-horizontal-track-Scottish Highers Physics-Question 3-2022.png

A student sets up an experiment to investigate the interaction between two trolleys on a smooth, horizontal track. The mass of trolley X is 0.50 kg and the mass of ... show full transcript

Worked Solution & Example Answer:A student sets up an experiment to investigate the interaction between two trolleys on a smooth, horizontal track - Scottish Highers Physics - Question 3 - 2022

Step 1

(a) (i) Calculate the magnitude of the change in momentum of trolley Y when the plunger is activated.

96%

114 rated

Answer

To calculate the change in momentum, we use the formula:

Δp=m(vfvi)\Delta p = m(v_f - v_i)

where:
m = mass of trolley Y = 0.25 kg,
v_f = final velocity of trolley Y = 1.80 m/s,
v_i = initial velocity of trolley Y = 0.40 m/s.

Substituting the values in:

Δp=0.25×(1.800.40)=0.25×1.40=0.35kgm/s\Delta p = 0.25 \times (1.80 - 0.40) = 0.25 \times 1.40 = 0.35 \, kg \, m/s

Step 2

(a) (ii) Calculate the time during which the plunger exerts a force on trolley Y.

99%

104 rated

Answer

Using the formula for force:

F=ΔpΔtF = \frac{\Delta p}{\Delta t}

Rearranging gives:

Δt=ΔpF\Delta t = \frac{\Delta p}{F}

Where:

  • (\Delta p = 0.35 , kg , m/s)
  • (F = 6.25 , N)

Substituting the values in:

Δt=0.356.25=0.056s\Delta t = \frac{0.35}{6.25} = 0.056 \, s

Step 3

(b) Calculate the velocity of trolley X immediately after the trolleys separate.

96%

101 rated

Answer

Using conservation of momentum:

mXvXi+mYvYi=mXvXf+mYvYfm_X v_{X_i} + m_Y v_{Y_i} = m_X v_{X_f} + m_Y v_{Y_f}

Where:

  • (m_X = 0.50 , kg)
  • (v_{X_i} = 0.40 , m/s)
  • (m_Y = 0.25 , kg)
  • (v_{Y_i} = 0.40 , m/s)
  • (v_{Y_f} = 1.80 , m/s)

Substituting values:

0.20 + 0.10 = 0.50 v_{X_f} + 0.45$$ Solving for \(v_{X_f}\): $$0.30 = 0.50 v_{X_f} + 0.45\ 0.30 - 0.45 = 0.50 v_{X_f}\ -0.15 = 0.50 v_{X_f}\ v_{X_f} = -0.30 \, m/s$$ This indicates that trolley X moves to the left.

Step 4

(c) Explain how the student would determine whether this interaction was elastic.

98%

120 rated

Answer

To determine if the interaction was elastic, the student should compare the total kinetic energy before and after the interaction. If the total kinetic energy remains the same, the interaction is elastic. However, if the total kinetic energy decreases, then it is inelastic.

Step 5

(d) (i) State the name of this effect.

97%

117 rated

Answer

The effect is known as the photovoltaic effect.

Step 6

(d) (ii) Explain the process occurring when photons of light are incident on the photodiode.

97%

121 rated

Answer

When light photons strike the photodiode, electrons gain energy and move from the valence band to the conduction band. This movement creates a flow of current and generates a potential difference across the diode, ultimately converting light energy into electrical energy.

Join the Scottish Highers students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;