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A block of wood slides with a constant velocity down a slope - Scottish Highers Physics - Question 3 - 2016

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A block of wood slides with a constant velocity down a slope. The slope makes an angle of 30° with the horizontal as shown. The mass of the block is 2.0 kg. The mag... show full transcript

Worked Solution & Example Answer:A block of wood slides with a constant velocity down a slope - Scottish Highers Physics - Question 3 - 2016

Step 1

Calculate the gravitational force acting on the block

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Answer

The gravitational force (weight) acting on the block can be calculated using the formula:

Fg=mimesgF_g = m imes g

Where:

  • m=2.0kgm = 2.0 \, kg (mass of the block)
  • g=9.8m/s2g = 9.8 \, m/s^2 (acceleration due to gravity)

Thus, Fg=2.0kg×9.8m/s2=19.6NF_g = 2.0 \, kg \times 9.8 \, m/s^2 = 19.6 \, N

Step 2

Calculate the component of the gravitational force parallel to the slope

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Answer

The component of the gravitational force acting parallel to the slope can be found using:

Fextparallel=Fg×sin(θ)F_{ ext{parallel}} = F_g \times \sin(\theta)

Where:

  • θ=30°\theta = 30°

Thus, Fextparallel=19.6N×sin(30°)=19.6N×0.5=9.8NF_{ ext{parallel}} = 19.6 \, N \times \sin(30°) = 19.6 \, N \times 0.5 = 9.8 \, N

Step 3

Determine the force of friction acting on the block

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Answer

Since the block is moving with constant velocity, the force of friction must equal the component of the gravitational force parallel to the slope:

Ff=Fextparallel=9.8NF_f = F_{ ext{parallel}} = 9.8 \, N

Thus, the magnitude of the force of friction acting on the block is 9.8N, which corresponds to option C.

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