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A car is travelling at 12 m/s along a straight road - Scottish Highers Physics - Question 2 - 2015

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A car is travelling at 12 m/s along a straight road. The car now accelerates uniformly at -1.5 m/s² for 6.0 s. The distance travelled during this time is A 18 m B ... show full transcript

Worked Solution & Example Answer:A car is travelling at 12 m/s along a straight road - Scottish Highers Physics - Question 2 - 2015

Step 1

Calculate the final velocity after acceleration

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Answer

To find the final velocity, we use the formula:

v=u+atv = u + at

where:

  • uu is the initial velocity (12 m/s)
  • aa is the acceleration (-1.5 m/s²)
  • tt is the time (6 s)

Substituting the values:

v=12+(1.5)(6)v = 12 + (-1.5)(6) v=129=3m/sv = 12 - 9 = 3 \, \text{m/s}

Step 2

Calculate the distance travelled during this time

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Answer

The distance travelled can be calculated using the formula:

d=ut+12at2d = ut + \frac{1}{2} a t^2

Substituting the known values:

  • u=12m/su = 12 \, \text{m/s}
  • a=1.5m/s2a = -1.5 \, \text{m/s}^2
  • t=6st = 6 \, \text{s}

Now, substituting into the formula:

d=(12)(6)+12(1.5)(6)2d = (12)(6) + \frac{1}{2}(-1.5)(6)^2

Calculating each term:

d=72+12(1.5)(36)d = 72 + \frac{1}{2}(-1.5)(36) d=7227=45md = 72 - 27 = 45 \, \text{m}

Step 3

Choose the correct answer from the options

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Answer

The distance travelled during this time is 45 m, which corresponds to option B.

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