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A triangular prism of borosilicate glass is placed inside a tank that has clear plastic walls - Scottish Highers Physics - Question 11 - 2022

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Question 11

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A triangular prism of borosilicate glass is placed inside a tank that has clear plastic walls. (a) A ray of monochromatic light passes through the glass prism and e... show full transcript

Worked Solution & Example Answer:A triangular prism of borosilicate glass is placed inside a tank that has clear plastic walls - Scottish Highers Physics - Question 11 - 2022

Step 1

Calculate angle θ.

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Answer

To find angle θ, we use Snell's Law:

n1sin(θ1)=n2sin(θ2)n_1 \sin(\theta_1) = n_2 \sin(\theta_2)

Here, for air, the refractive index n1=1n_1 = 1 and for borosilicate glass, n2=1.47n_2 = 1.47.

Let heta1=37° heta_1 = 37° and heta2=θ heta_2 = θ.

Substituting the values: 1sin(37°)=1.47sin(θ)1 \cdot \sin(37°) = 1.47 \cdot \sin(θ)

Calculating: sin(θ)=sin(37°)1.47\sin(θ) = \frac{\sin(37°)}{1.47}

Using a calculator, we find:

θ26.2°θ \approx 26.2°.

Step 2

Calculate the critical angle of the glass for this light.

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Answer

The critical angle, θcθ_c, can be calculated using:

sin(θc)=n2n1\sin(θ_c) = \frac{n_2}{n_1}

Where n1=1n_1 = 1 (air) and n2=1.47n_2 = 1.47 (glass).

Thus: sin(θc)=1.471\sin(θ_c) = \frac{1.47}{1}

This yields: θc42.9°.θ_c \approx 42.9°.

Step 3

State at which point, P, Q, R, S, or T, the ray of light will now leave the plastic tank. Justify your answer.

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Answer

The ray of light will leave the plastic tank at point P. This is because the refractive index of the vegetable oil is the same as that of the glass, hence there will be no refraction or change in speed/wavelength at this interface.

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