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Calculations Involving the Equilibrium Constant Simplified Revision Notes

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1.8.4 Calculations Involving the Equilibrium Constant

Calculating the equilibrium constant KcK_c involves determining the concentrations of reactants and products at equilibrium and using them in the expression for KcK_c. These calculations are essential for predicting the position of equilibrium and understanding the extent of a reaction under specific conditions.

Units of KcK_c

The units of KcK_c depend on the reaction's stoichiometry.

In this example:

Kc=(mol dm3)×(mol dm3)mol dm3=mol dm3K_c = \frac{(\text{mol dm}^{-3}) \times (\text{mol dm}^{-3})}{\text{mol dm}^{-3}} = \text{mol dm}^{-3}

Thus:

Kc=:highlight[0.09mol dm3]K_c = :highlight[0.09 \, \text{mol dm}^{-3}]

Worked Example Calculating KcK_c

infoNote

Example: How to Calculate KcK_c

Step 1: Write the Balanced Equation

Start with the balanced equation for the reversible reaction. This helps determine the correct expression for KcK_c

Example: For the reaction

PCl5(g)PCl3(g)+Cl2(g)PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)

The equilibrium expression for KcK_c is:

Kc=[PCl3][Cl2][PCl5]K_c = \frac{[PCl_3][Cl_2]}{[PCl_5]}

Step 2: Calculate Moles at Equilibrium

Use the information provided to calculate the moles of each species at equilibrium.

In the example, if 2.00 moles of PCl5PCl_5 are placed in a 20 dm3dm^3 container and at equilibrium, 1.20 moles of Cl2Cl_2 are present:

Moles of PCl5PCl_5 at equilibrium = Initial moles - Moles of Cl2Cl_2

2.001.20=:highlight[0.80 moles of PCl5]2.00 - 1.20 = :highlight[0.80 \text{ moles of } PCl_5]

Moles of PCl3PCl_3 at equilibrium = 1.20 (since 1 mole of PCl3PCl_3 is produced for every mole of Cl2Cl_2).


Step 3: Calculate Concentrations

Convert the moles into concentrations by dividing the number of moles by the volume of the container in dm3dm^3

For PCl5PCl_5, PCl3PCl_3, and Cl2Cl_2:

[PCl5]=0.80 mol20 dm3=:highlight[0.04 mol dm3][PCl_5] = \frac{0.80 \text{ mol}}{20 \text{ dm}^3} = :highlight[0.04 \text{ mol dm}^{-3}][PCl3]=1.20 mol20 dm3=:highlight[0.06 mol dm3][PCl_3] = \frac{1.20 \text{ mol}}{20 \text{ dm}^3} = :highlight[0.06 \text{ mol dm}^{-3}][Cl2]=1.20 mol20 dm3=:highlight[0.06 mol dm3][Cl_2] = \frac{1.20 \text{ mol}}{20 \text{ dm}^3} = :highlight[0.06 \text{ mol dm}^{-3}]

Step 4: Substitute into the K_c Expression

Substitute the concentrations into the expression for KcK_c:

Kc=[PCl3][Cl2][PCl5]K_c = \frac{[PCl_3][Cl_2]}{[PCl_5]} =0.06×0.060.04=:highlight[0.09 mol dm3]= \frac{0.06 \times 0.06}{0.04} = :highlight[0.09 \text{ mol dm}^{-3}]
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