Photo AI

Last Updated Sep 27, 2025

The Ionic Product of Water Simplified Revision Notes

Revision notes with simplified explanations to understand The Ionic Product of Water quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

467+ students studying

5.5.3 The Ionic Product of Water

Dissociation of Water

Water is only slightly dissociated, meaning it ionizes very minimally in solution. This dissociation creates a balance of hydrogen ions H+\text{H}^+ and hydroxide ions OH\text{OH}^-, represented by the equilibrium:

H2OH++OH\text{H}_2\text{O} \rightleftharpoons \text{H}^+ + \text{OH}^-

Since the dissociation is minimal, this equilibrium lies far to the left.

The Ionic Product of Water (KwK_w)

The equilibrium constant for the dissociation of water is called the ionic product of water KwK_w.

It is defined as:

Kw=[H+][OH]K_w = [\text{H}^+][\text{OH}^-]

At 25°C, KwK_w has a value of 1.00 × 10⁻¹⁴ mol² dm⁻⁶

This value varies with temperature, as water dissociation is an endothermic process, meaning KwK_w increases with temperature.

Units of KwK_w: The units for KwK_w are always mol² dm⁻⁶

Calculating the pH of Pure Water

In pure water, the concentration of H+\text{H}^+ is equal to the concentration of OH\text{OH}^-.

Therefore:

Kw=[H+]2K_w = [\text{H}^+]^2 [H+]=Kw[\text{H}^+] = \sqrt{K_w}
infoNote

Example Calculation: pH of Water at 40°C

Given at 40°C:

Kw=2.92×1014mol2dm6K_w = 2.92 \times 10^{-14} \, \text{mol}^2 \, \text{dm}^{-6}

Calculate [H+][\text{H}^+]:

[H+]=2.92×1014=1.709×107mol dm3[\text{H}^+] = \sqrt{2.92 \times 10^{-14}} = 1.709 \times 10^{-7} \, \text{mol dm}^{-3}

Calculate pH:

pH=log10(1.709×107)6.77\text{pH} = -\log_{10} (1.709 \times 10^{-7}) \approx 6.77

This result shows that the pH of pure water decreases slightly with increased temperature because more H+\text{H}^+ ions are produced as KwK_w rises.

Calculating the pH of a Strong Base Using KwK_w

For a strong base like sodium hydroxide NaOH\text{NaOH}, which fully dissociates, you can use KwK_w to find the H+\text{H}^+ concentration and calculate the pH.

infoNote

Example Calculation: pH of a 0.250 M NaOH\text{NaOH} Solution

Determine [OH][\text{OH}^-]

Since NaOH\text{NaOH} fully dissociates,

[OH]=0.250mol dm3[\text{OH}^-] = 0.250 \, \text{mol dm}^{-3}

Use KwK_w to Find [H+][\text{H}^+]

Kw=[H+][OH]K_w = [\text{H}^+][\text{OH}^-][H+]=Kw[OH]=1.00×10140.250[\text{H}^+] = \frac{K_w}{[\text{OH}^-]} = \frac{1.00 \times 10^{-14}}{0.250} =4.00×1014mol dm3= 4.00 \times 10^{-14} \, \text{mol dm}^{-3}

Calculate pH:

pH=log10(4.00×1014)=13.40\text{pH} = -\log_{10} (4.00 \times 10^{-14}) = 13.40

The high pH value aligns with expectations for a strong base solution, confirming it's highly alkaline.

infoNote

Summary

  • Dissociation of Water: Produces equal concentrations of H+\text{H}^+ and OH\text{OH}^- ions in pure water.
  • Ionic Product of Water: Defined as Kw=[H+][OH]K_w = [\text{H}^+][\text{OH}^-], varies with temperature.
  • Calculating pH: Use KwK_w to find [H+][\text{H}^+] in basic solutions, then calculate pH using pH=log10[H+]\text{pH} = -\log_{10} [\text{H}^+]
Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master The Ionic Product of Water

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

30 flashcards

Flashcards on The Ionic Product of Water

Revise key concepts with interactive flashcards.

Try Chemistry Flashcards

3 quizzes

Quizzes on The Ionic Product of Water

Test your knowledge with fun and engaging quizzes.

Try Chemistry Quizzes

29 questions

Exam questions on The Ionic Product of Water

Boost your confidence with real exam questions.

Try Chemistry Questions

27 exams created

Exam Builder on The Ionic Product of Water

Create custom exams across topics for better practice!

Try Chemistry exam builder

21 papers

Past Papers on The Ionic Product of Water

Practice past papers to reinforce exam experience.

Try Chemistry Past Papers

Other Revision Notes related to The Ionic Product of Water you should explore

Discover More Revision Notes Related to The Ionic Product of Water to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Fundamentals of Acids & Bases (A Level only)

Brønsted–Lowry Acid & Bases

user avatar
user avatar
user avatar
user avatar
user avatar

206+ studying

189KViews

96%

114 rated

Fundamentals of Acids & Bases (A Level only)

pH & Hydrogen Ions

user avatar
user avatar
user avatar
user avatar
user avatar

383+ studying

186KViews
Load more notes

Join 500,000+ A-Level students using SimpleStudy...

Join Thousands of A-Level Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered