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Using SUVAT Simplified Revision Notes

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2.6.2 Using SUVAT

The SUVAT equations are a set of five kinematic equations that describe the motion of an object under constant acceleration. These equations are fundamental in mechanics and are particularly useful for solving problems involving linear motion in a straight line.

1. What Does SUVAT Stand For?

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Each letter in SUVAT represents a different physical quantity:

  • S: Displacement (in metres, mm )
  • U: Initial velocity (in metres per second, m/sm/s )
  • V: Final velocity (in metres per second, m/sm/s )
  • A: Acceleration (in metres per second squared, m/s2m/s^2 )
  • T: Time (in seconds, ss )

2. The Five SUVAT Equations

These equations link the five quantities and allow you to solve for one when you know the others:

infoNote
  1. v = u + at
  • Description: Final velocity after time tt with initial velocity uu and constant acceleration aa .
  • Use: When you need to find final velocity or time.
  1. s=ut+12at2s = ut + \frac{1}{2}at^2
  • Description: Displacement after time tt with initial velocity uu and constant acceleration a a .
  • Use: When you need to find displacement.
  1. s=vt12at2s = vt - \frac{1}{2}at^2
  • Description: Displacement after time tt with final velocity vv and constant acceleration aa .
  • Use: When you have final velocity and time and need to find displacement.
  1. s=u+v2×ts = \frac{u + v}{2} \times t
  • Description: Displacement when you know both the initial and final velocities over a period of time tt .
  • Use: When you need to find displacement without knowing acceleration.
  1. v2=u2+2asv^2 = u^2 + 2as
  • Description: Final velocity squared when you know initial velocity, acceleration, and displacement.
  • Use: When you need to find final velocity or displacement without involving time.

3. Applying the SUVAT Equations

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To effectively use the SUVAT equations, follow these steps: 6. Identify Known and Unknown Quantities:

  • Write down what is given in the problem (e.g., initial velocity uu , time tt , etc.).
  • Identify which quantity you need to find (e.g., final velocity vv ).
  1. Choose the Appropriate Equation:
  • Select the SUVAT equation that includes the known quantities and the one you need to find.
  • Ensure that you have at least three known variables to solve for the unknown.
  1. Solve the Equation:
  • Substitute the known values into the equation.
  • Rearrange the equation if necessary to solve for the unknown quantity.
  1. Check Units and Reasonableness:
  • Ensure all quantities are in consistent units (e.g., metres, seconds).
  • Check if the result makes sense in the context of the problem.

4. Example Problems Using SUVAT Equations

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Example 1: A car accelerates from rest at 2m/s22 \, m/s^2 for 55 seconds. What is its final velocity?

  • Given: u=0m/su = 0 \, m/s (from rest), a=2m/s2a = 2 \, m/s^2 , t=5st = 5 \, s
  • To Find: Final velocity vv Using v=u+atv = u + at :

v=0+(2)(5)=10m/sv = 0 + (2)(5) = 10 \, m/s

The final velocity is 10 m/s .

infoNote

Example 2: A ball is thrown upwards with an initial velocity of 15m/s15 \, m/s . Find the maximum height it reaches.

  • Given: u=15m/su = 15 \, m/s , v=0m/sv = 0 \, m/s (at maximum height), a=9.8m/s2a = -9.8 \, m/s^2 (gravity, acting downwards)
  • To Find: Displacement ss (maximum height) Using v2=u2+2asv^2 = u^2 + 2as :

0=(15)2+2(9.8)s0 = (15)^2 + 2(-9.8)s

0=22519.6s0 = 225 - 19.6s

19.6s=22519.6s = 225

s=22519.611.48ms = \frac{225}{19.6} \approx 11.48 \, m

The maximum height reached is approximately 11.48 m .

5. Tips for Using SUVAT Equations

infoNote
  • Consistent Sign Convention: Choose a direction as positive (usually upwards or forwards) and stick to it throughout the problem.
  • Use Gravity Correctly: When dealing with vertical motion, remember that the acceleration due to gravity is -9.8 m/s² (downwards).
  • Recognise When to Use Each Equation: Understand which SUVAT equation is best for the given situation, based on what you know and what you need to find.
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