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Discriminants Simplified Revision Notes

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2.2.2 Discriminants

Discriminants in Quadratic Equations

The discriminant is a key concept in the study of quadratic equations, typically of the form:

ax2+bx+c=0ax^2 + bx + c = 0

where aa, (b), and (c) are constants, and a0a \neq 0. The discriminant is a part of the quadratic formula, which is used to find the roots (solutions) of the quadratic equation:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The discriminant, denoted by the symbol ( \Delta ), is the expression under the square root:

Δ=b24ac \Delta = b^2 - 4ac

Interpretation of the Discriminant

The discriminant tells us about the nature of the roots of the quadratic equation:

IfΔ>0:If \Delta > 0 :
  • The quadratic equation has two distinct real roots.
  • The roots are unequal and real.
IfΔ=0:If \Delta = 0 :
  • The quadratic equation has one real root (or two equal real roots).
  • The root is real and repeated.
IfΔ<0:If \Delta < 0 :
  • The quadratic equation has no real roots.
  • The roots are complex (conjugate pairs).

Examples:

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Example 1:

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Example 2:

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Example 3:

Past Edexcel Exam Question:

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June 2017, Paper 1, Question 6: "Given the quadratic equation  3x2+2kx+k=0\ 3x^2 + 2kx + k = 0, find the range of values of kk for which the equation has two distinct real roots."

Solution Outline:

  1. Discriminant Condition:
  • For two distinct real roots, Δ>0\Delta > 0 .
  • The discriminant Δ=(2k)24(3)(k)=4k212k\Delta = (2k)^2 - 4(3)(k) = 4k^2 - 12k.
  1. Set Up the Inequality:
  • 4k212k>0. 4k^2 - 12k > 0 .
  • Factorize: 4k(k3)>0. 4k(k - 3) > 0 .
  1. Solve the Inequality:
  • The critical points are (k=0)( k = 0 ) and (k=3)( k = 3 ).
  • The quadratic inequality k(k3)>0\ k(k - 3) > 0 gives (k<0) ( k < 0 ) or (k>3)( k > 3 ).
  1. Conclusion:
  • The equation has two distinct real roots for (k<0)\ ( k < 0 ) or (k>3)( k > 3 ). This example uses the discriminant to determine the conditions under which a quadratic equation has two distinct real roots.

Curve Sketching Using the Discriminant

When sketching the graph of a quadratic function  y=ax2+bx+c,\ y = ax^2 + bx + c , the discriminant Δ=b24ac\Delta = b^2 - 4ac plays a crucial role in determining the nature and number of roots (x-intercepts) of the curve, which is a parabola.

Key Features of the Parabola:

  1. Direction:
  • a>0a > 0: The parabola opens upwards.
  • a<0a < 0: The parabola opens downwards.
  1. Vertex:
  • The x-coordinate of the vertex is  x=b2a\ x = -\frac{b}{2a} .
  • Substitute this x-value into the equation to find the y-coordinate.
  1. Y-Intercept:
  • The y-intercept is  c\ c , since y=c\ y = c when x=0. x = 0 .
  1. X-Intercepts:
  • The discriminant Δ=b24ac\Delta = b^2 - 4ac determines the number of x-intercepts:
  • Δ>0\Delta > 0: Two distinct real roots (two x-intercepts).
  • Δ=0\Delta = 0: One real root (the vertex touches the x-axis).
  • Δ<0\Delta < 0: No real roots (the parabola does not touch the x-axis).

Steps for Sketching the Curve:

  1. Determine the Direction:
  • Check the sign of  a\ a to see if the parabola opens upwards or downwards.
  1. Find the Vertex:
  • Calculate the vertex using x=b2ax = -\frac{b}{2a} and find the corresponding y-coordinate.
  1. Plot the Y-Intercept:
  • The y-intercept is at  (0,c).\ (0, c) .
  1. Analyse the Discriminant:
  • Calculate Δ=b24ac\Delta = b^2 - 4ac to determine the number of x-intercepts.
  • If  Δ>0\ \Delta > 0 , solve for the roots using the quadratic formula to find the x-intercepts.
  1. Plot Key Points:
  • Plot the vertex, yintercepty-intercept, and any xinterceptsx-intercepts.
  • Draw a smooth curve through these points, ensuring it opens in the correct direction.
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Example:

For  y=x24x+3\ y = x^2 - 4x + 3 :

  • Direction:  a=1\ a = 1 (upwards).
  • Vertex:  x=2\ x = 2 ,  y=1\ y = 1 (vertex at (2,1) (2, 1)).
  • Y-Intercept:  (0,3)\ (0, 3) .
  • Discriminant:  Δ=4\ \Delta = 4 (two real roots).
  • X-Intercepts: (1,0)(1, 0) and (3,0)(3, 0) Plot these points and sketch the parabola opening upwards.

This concise approach helps you efficiently sketch quadratic curves using the discriminant and key features.


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