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Binomial Expansion Simplified Revision Notes

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4.1.1 Binomial Expansion

Binomial Expansions

Binomial Theorem:

infoNote

The binomial expansion is the process of expanding expressions of the form (a+b)n(a + b)^n, where nn is a non-negative integer. The formula for the expansion is given by the Binomial Theorem:

(a+b)n=k=0n(nk)ankbk(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

Where:

  • (nk)\binom{n}{k} is the binomial coefficient, read as "n choose k," and is given by:
(nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}
  • n! n! is the factorial of nn.
  • anka^{n-k} is the term involving aa, and bk b^k is the term involving bb.

General Form of the Expansion:

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The binomial expansion of (a+b)n(a + b)^n will look like this:

(a+b)n=an+(n1)an1b+(n2)an2b2++bn(a + b)^n = a^n + \binom{n}{1} a^{n-1}b + \binom{n}{2} a^{n-2}b^2 + \cdots + b^n

Each term in the expansion consists of:

  1. Binomial Coefficient: (nk)\binom{n}{k}
  2. A power of aa, starting from ana^n and decreasing to a0a^0.
  3. A power of bb, starting from b0b^0 and increasing to bnb^n.

Examples:

infoNote
  1. Example 1: Expand (x+y)2(x + y)^2 :
(x+y)2=x2+2xy+y2(x + y)^2 = x^2 + 2xy + y^2

Using the Binomial Theorem:

  • The first term is x2x^2, with a binomial coefficient of (20)=:success[1]\binom{2}{0} = :success[1] .
  • The second term is 2xy2xy, with a binomial coefficient of (21)=:success[2]\binom{2}{1} = :success[2] .
  • The third term is y2y^2, with a binomial coefficient of (22)=:success[1]\binom{2}{2} = :success[1] .
  1. Example 2: Expand (x+1)3(x + 1)^3 :
(x+1)3=x3+3x2+3x+1(x + 1)^3 = x^3 + 3x^2 + 3x + 1

Using the Binomial Theorem:

  • The first term is x3 x^3, with a binomial coefficient of (30)=:success[1]\binom{3}{0} = :success[1].
  • The second term is 3x23x^2, with a binomial coefficient of (31)=:success[3]\binom{3}{1} = :success[3].
  • The third term is 3x3x, with a binomial coefficient of (32)=:success[3]\binom{3}{2} = :success[3].
  • The fourth term is 11, with a binomial coefficient of (33)=:success[1]\binom{3}{3} = :success[1].
infoNote

Binomial Coefficients:

The binomial coefficients (nk)\binom{n}{k} are the numbers that appear in Pascal's Triangle, and they can be computed using the formula:

(nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}

Where n!n! (factorial of nn) is the product of all positive integers up to nn.

Pascal's Triangle:

Pascal's Triangle is a triangular array of numbers, where each number is the sum of the two directly above it. The n n-th row gives the binomial coefficients for (a+b)n(a + b)^n .

For example, the first few rows of Pascal's Triangle are:

       1
      1 1
     1 2 1
    1 3 3 1
   1 4 6 4 1

Properties of Binomial Expansion:

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  1. The total number of terms in the expansion of (a+b)n(a + b)^n is n + 1 .
  2. The sum of the exponents of aa and bb in each term is always nn.
  3. The binomial expansion can be applied to both positive and negative terms as long as nn is a non-negative integer.

Special Cases:

infoNote
  1. For (ab)n(a - b)^n: The expansion follows the same pattern as (a+b)n(a + b)^n, except the signs alternate.
(ab)n=an(n1)an1b+(n2)an2b2+(1)nbn(a - b)^n = a^n - \binom{n}{1} a^{n-1} b + \binom{n}{2} a^{n-2} b^2 - \cdots + (-1)^n b^n
  1. For fractional or negative exponents, the binomial expansion becomes an infinite series and requires more advanced methods (not covered in basic binomial expansion).

Applications of Binomial Expansion:

  1. Algebraic Expansion: Simplifying powers of binomials like (a+b)n.(a + b)^n.
  2. Approximations: In cases where nn is large, binomial expansion helps in approximation methods.
  3. Probability: Binomial coefficients appear in binomial probability distributions.

Counting Combinations

  1. Picking 2 different colours from 4 colours:
  • When the order of choosing is not important, we have: (42)=:success[6]\binom{4}{2} = :success[6]
  • This is because there are 6 different ways to choose 22 colours out of 4.4.
image
  1. Picking 3 different colours from 4 colours:
  • Again, when the order of choosing is not important, we have: (43)=:success[4]\binom{4}{3} = :success[4]
  • This is because there are 4 different ways to choose 33 colours out of 44. image

General Formula

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The binomial coefficient (combinations) is given by: nCr=nCr=(nr)=n!r!(nr)!{}^nC_r = {}_nC_r = \binom{n}{r} = \frac{n!}{r!(n-r)!}

(nr)=n!r!(nr)!\dbinom{n}{r} = \dfrac{n!}{r!(n-r)!}

infoNote

Example Calculations

  1. Choosing 22 out of 4 4: (42)=4!2!(42)!=4×3×2×12×1×2×1=244=:success[6]\binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3 \times 2 \times 1}{2 \times 1 \times 2 \times 1} = \frac{24}{4} = :success[6]

Table of Combinations

Number of Colours Chosen (from 4)Number of Ways
01
14
26
34
41

The formula for combinations ensures that we count the number of ways to choose items without regard to the order of selection.

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