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5.7.1 Strategy for Further Trigonometric Equations

Solving further trigonometric equations often involves more complex strategies than basic trigonometric equations. These equations might involve multiple angles, compound angles, or require the use of identities like double-angle or sum-to-product identities. Here's a strategy to approach and solve these types of equations:

1. Understand the Equation

  • Identify which trigonometric functions and identities are involved (e.g., sine, cosine, tangent, double angles, sum/difference of angles).
  • Determine if the equation involves compound angles, multiple angles, or identities that can be simplified.

2. Simplify Using Trigonometric Identities

  • Expand or Factor: If the equation involves compound angles (e.g., sin(A+B)\sin(A + B)), use the sum/difference identities to expand them.
  • Use Double-Angle or Half-Angle Identities: If the equation involves double angles (e.g., sin2θ\sin 2\theta), apply the double-angle identities: sin2θ=2sinθcosθ,cos2θ=2cos2θ1 or 12sin2θ\sin 2\theta = 2\sin \theta \cos \theta, \quad \cos 2\theta = 2\cos^2 \theta - 1 \text{ or } 1 - 2\sin^2 \theta
  • Convert Products to Sums: If the equation involves products of trigonometric functions, use product-to-sum identities: sinAsinB=12[cos(AB)cos(A+B)]\sin A \sin B = \frac{1}{2} [\cos(A - B) - \cos(A + B)]
  • Simplify Complex Fractions: If the equation has fractions, multiply both sides by a common denominator to simplify.

3. Isolate the Trigonometric Function

  • Isolate: Try to isolate one trigonometric function on one side of the equation. For example, if you have: 2sinθ+3=02 \sin \theta + \sqrt{3} = 0 Isolate  sinθ by subtracting 3\ \sin \theta \ by\ subtracting \ \sqrt{3} from both sides and dividing by 22.

4. Use Substitution If Necessary

  • If the equation is quadratic in form, or involves multiple trigonometric terms (e.g.,  sin2θ\ \sin^2 \theta ) and ( sinθ\sin \theta ), use substitution:
    • Let u=sinθ ( or cosθ) u = \sin \theta \ (\ or \ \cos \theta), solve the resulting quadratic equation for  u\ u , then back-substitute to find θ. \theta .

5. Consider All Possible Solutions

  • General Solution: Trigonometric functions are periodic, so after solving for the basic angle, consider the general solution:
    • For  sinθ=k or cosθ=k:\ \sin \theta = k \ or \ \cos \theta = k : θ=θ0+360norθ=180θ0+360n\theta = \theta_0 + 360^\circ n \quad \text{or} \quad \theta = 180^\circ - \theta_0 + 360^\circ n
    • For tanθ=k: \tan \theta = k : θ=θ0+180n\theta = \theta_0 + 180^\circ n
  • Specific Interval: If the problem specifies an interval (e.g., 0θ3600^\circ \leq \theta \leq 360^\circ), ensure that all solutions fall within this interval.

6. Check for Extraneous Solutions

  • After solving, substitute your solutions back into the original equation to ensure they satisfy it.
  • Extraneous solutions often arise when you square both sides of an equation or use an identity that introduces additional roots.

7. Special Cases and Techniques

  • Using Sum and Difference Identities: If the equation involves terms like sin(A±B),\sin(A \pm B) ,expand them using: sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B
  • Using RR Addition Formulae: If the equation is of the form acosθ+bsinθ=c,\ a \cos \theta + b \sin \theta = c ,consider using the R addition formula: Rcos(θ±α)=acosθ+bsinθR \cos(\theta \pm \alpha) = a \cos \theta + b \sin \theta Where  R=a2+b2 andtanα=ba.\ R = \sqrt{a^2 + b^2} \ and \tan \alpha = \frac{b}{a} .

Example Problems:

infoNote

Example 1: Solve sin2θ=3cosθ for  0θ360. \sin 2\theta = \sqrt{3} \cos \theta \ for\ \ 0^\circ \leq \theta \leq 360^\circ .


  • Step 1: Simplify Using Identities:
  • Use the double-angle identity: sin2θ=2sinθcosθ. \sin 2\theta = 2 \sin \theta \cos \theta .  2sinθcosθ=3cosθ\ 2 \sin \theta \cos \theta = \sqrt{3} \cos \theta
  • Step 2: Isolate the Trigonometric Function:
  • Factor out  cosθ:\ \cos \theta : cosθ(2sinθ3)=0\cos \theta (2 \sin \theta - \sqrt{3}) = 0
  • Step 3: Solve Each Factor:
  •  cosθ=0 θ=90,270\ \cos \theta = 0 \: \ \theta = 90^\circ, 270^\circ
  • 2sinθ3=0 sinθ=322 \sin \theta - \sqrt{3} = 0 \: \ \sin \theta = \frac{\sqrt{3}}{2}
  • θ=60,120\theta = 60^\circ, 120^\circ
  • Final Solutions:
  • θ=:success[60,90,120,270]. \theta = :success[60^\circ, 90^\circ, 120^\circ, 270^\circ] .
infoNote

Example 2: Solve cos2θ=1sinθ\cos^2 \theta = 1 - \sin \theta for 0θ360. 0^\circ \leq \theta \leq 360^\circ .


  • Step 1: Simplify Using Identities:
  • Use the Pythagorean identity cos2θ=1sin2θ: \cos^2 \theta = 1 - \sin^2 \theta : 1sin2θ=1sinθ1 - \sin^2 \theta = 1 - \sin \theta
  • Step 2: Rearrange and Factor:
  • Rearrange to form a quadratic equation: sin2θsinθ=0\sin^2 \theta - \sin \theta = 0
  • Factor: sinθ(sinθ1)=0\sin \theta (\sin \theta - 1) = 0
  • Step 3: Solve Each Factor:
  •  sinθ=0 θ=0,180\ \sin \theta = 0 \: \ \theta = 0^\circ, 180^\circ
  •  sinθ=1 θ=90\ \sin \theta = 1 \: \ \theta = 90^\circ
  • Final Solutions:
  • θ=:success[0,90,180]\theta = :success[0^\circ, 90^\circ, 180^\circ].

Summary:

infoNote
  • Simplify the equation using trigonometric identities, focusing on isolating trigonometric functions or reducing the equation's complexity.
  • Use substitution when dealing with quadratic or more complex forms, and always consider the general solutions due to the periodic nature of trigonometric functions.
  • Check all potential solutions within the given interval and verify them against the original equation to avoid extraneous solutions.
  • Special techniques like the RR addition formula or sum-to-product identities can greatly simplify solving more complicated equations.
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