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Exponential Equations Simplified Revision Notes

Revision notes with simplified explanations to understand Exponential Equations quickly and effectively.

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6.2.2 Exponential Equations

Solving Exponential Equations

infoNote

Example 1: 5x=2.85^x = 2.8

  • Problem: xx is in the power and needs to be "brought down."

  • Solution: Take logs of both sides. log(5x)=log(2.8) \log(5^x) = \log(2.8)

  • Apply the logarithm rule: log(ab)=blog(a)\log(a^b) = b\log(a) xlog(5)=log(2.8) x \cdot \log(5) = \log(2.8)

  • Solve for xx: x=log(2.8)log(5):highlight[0.640](3sf) x = \frac{\log(2.8)}{\log(5)} \approx :highlight[0.640] \quad \text{(3sf)}

Alternative Solution with Different Base Logs

Given the same equation 5x=2.85^x = 2.8:

ln(5x)=ln(2.8) \ln(5^x) = \ln(2.8)

  • Apply the same logarithm rule: xln(5)=ln(2.8) x \cdot \ln(5) = \ln(2.8)

  • Solve for xx: x=ln(2.8)ln(5):highlight[0.640](3sf) x = \frac{\ln(2.8)}{\ln(5)} \approx :highlight[0.640] \quad \text{(3sf)}

Note: There is no rule for combining different logarithm bases directly.

infoNote

Example 2: 2x+3=7.22^{x+3} = 7.2

log(2x3)=log(7.2) \log(2^{x-3}) = \log(7.2)

  • Apply the logarithm rule: (x3)log(2)=log(7.2)(x - 3) \cdot \log(2) = \log(7.2)

  • Solve for xx: x3=log(7.2)log(2):highlight[2.85](3sf)x - 3 = \frac{\log(7.2)}{\log(2)} \approx :highlight[2.85] \quad \text{(3sf)}

x:highlight[2.85+3=5.85](3sf)x \approx :highlight[2.85 + 3 = 5.85] \quad \text{(3sf)}

infoNote

Example 3: log(2x+3)=2log(3)+log(54x)\log(2^{x+3}) = 2\log(3) + \log(5^{4-x})

  • Expand and rearrange: (x+3)log(2)=2log(3)+(4x)log(5)(x + 3)\log(2) = 2\log(3) + (4-x)\log(5)

  • Group the logarithm terms: xlog(2)+3log(2)=2log(3)+4log(5)xlog(5)x\log(2) + 3\log(2) = 2\log(3) + 4\log(5) - x\log(5)

  • Collect like terms: xlog(2)+xlog(5)=2log(3)+4log(5)3log(2) x\log(2) + x\log(5) = 2\log(3) + 4\log(5) - 3\log(2)

x(log(2)+log(5))=2log(3)+4log(5)3log(2)x(\log(2) + \log(5)) = 2\log(3) + 4\log(5) - 3\log(2)

  • Solve for xx: x=2log(3)+4log(5)3log(2)log(2)+log(5)x = \frac{2\log(3) + 4\log(5) - 3\log(2)}{\log(2) + \log(5)}

Final Simplified Equation:

x(log(2)+log(5))=2log(3)+4log(5)3log(2)x(\log(2) + \log(5)) = 2\log(3) + 4\log(5) - 3\log(2)

x=log(22)+log(54)log(23)log(2)+log(5):highlight[1.73]x = \frac{\log(2^2) + \log(5^4) - \log(2^3)}{\log(2) + \log(5)} \approx :highlight[1.73]

Solving Logarithmic Equations

log3(32.173)=2.1736log6(0.32)=0.32 \log_3(3^{2.173}) = 2.173 \quad 6^{log_6({0.32})} = 0.32

log7(79.46)=9.464log4(9.1)=9.1\log_7(7^{9.46}) = 9.46 \quad 4^{log_4({9.1})} = 9.1

logΠ(Π8.4)=8.43log3(12)=12\log_\Pi(\Pi^{8.4}) = 8.4 \quad 3^{log_3({12})} = 12

Explanation:

log4(0.6)\log_{4}(0.6) asks: what power do I give 66 to get 0.60.6?

If I then give it that power, I get 0.60.6:

4log4(0.6))=0.64^{\log_{4}(0.6)}\text{)} = 0.6

This idea can be applied to solving logarithmic equations.

infoNote

Example 1: log6(x)=0.2 \log_{6}(x) = 0.2

6log6(x)=60.2(Raise 6 to both sides)\Rightarrow 6^{\log_{6}(x)} = 6^{0.2} \quad \text{(Raise } 6 \text{ to both sides)}

x=60.2=:highlight[1.431]\Rightarrow x = 6^{0.2} = :highlight[1.431]\ldots (4sf) (4sf)

infoNote

Example 2: log12(4x)=1/3\log_{12}(4x) = 1/3

12log12(4x)=121/3(Raise 12 to both sides)\Rightarrow 12^{\log_{12}(4x)} = 12^{1/3} \quad \text{(Raise } 12 \text{ to both sides)}

$ \Rightarrow 4x = 12^{1/3}

$

x=121/34=:highlight[0.5724] (Approx.)\Rightarrow x = \frac{12^{1/3}}{4} = :highlight[0.5724]\ldots \text{ (Approx.)} (4sf)(4sf)

infoNote

Example 3: log(x)+2log(x)=4\log(x) + 2 \log(x) = 4

$ \Rightarrow \log(x )+

\log(x^{2}) = 4$

\Rightarrow$$\log(x^{3}) = 4

$ \Rightarrow 10^{\log(x^{3})} = 10^4 \Rightarrow x^{3} = 10^4

$

x=1043=:highlight[21.54] (4sf)x =10^\frac{{4}}{3} = :highlight[21.54] \ (4sf)

Wrong Method:

10log(x)+102logx=10410^{log(x)}+10^{2logx}=10^4 because

1+2=3101+102=1031+2 = 3 \nRightarrow 10^1+10^2=10^3

Ensure a single term on each side

infoNote
infoNote
  1. log10(x210x)(Subtraction rule)\log_{10}\left(\frac{x^2 - 10}{x}\right) \quad \text{(Subtraction rule)}

  2. log10(x210x)=2log10(3)\log_{10}\left(\frac{x^2 - 10}{x}\right) = 2 \log_{10} (3)

log10(x210x)=log10(9)\Rightarrow \log_{10}\left(\frac{x^2 - 10}{x}\right) = \log_{10}(9)

10log10(x210x)=10log10(9)\Rightarrow 10^{\log_{10}\left(\frac{x^2 - 10}{x}\right)} = 10^{\log_{10}(9)}

x210x=9\Rightarrow \frac{x^2 - 10}{x} = 9

x210=9x\Rightarrow x^2 - 10 = 9x

x29x10=0\Rightarrow x^2 - 9x - 10 = 0

(x10)(x+1)=0\Rightarrow (x - 10)(x + 1) = 0

:success[x=10]orx=1\Rightarrow :success[x = 10] \quad \text{or} \quad x = -1

(Note: x = -1 is not valid because logarithms of negatives do not exist.)


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