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8.3.1 General Solutions

In A Level Maths, particularly within the topic of differential equations, finding the general solution is a key skill. A differential equation involves an unknown function and its derivatives, and solving it means finding a function (or a family of functions) that satisfies the equation.

Types of Differential Equations

  1. First-Order Differential Equations: Involve the first derivative of the unknown function (e.g., dydx\frac{dy}{dx}.
  2. Second-Order Differential Equations: Involve up to the second derivative of the unknown function (e.g., d2ydx2\frac{d^2y}{dx^2}).

General Solution

The general solution of a differential equation is the most general form of the solution, typically containing one or more arbitrary constants. These constants can take any value and represent the infinite set of solutions to the equation.

1. First-Order Differential Equations

A first-order differential equation can usually be written in the form:

dydx=f(x,y)\frac{dy}{dx} = f(x, y)

infoNote

📑Example 1: Separable Equations For a separable differential equation, the variables can be separated on either side of the equation:

dydx=g(x)h(y)\frac{dy}{dx} = g(x) h(y)

The general solution involves integrating both sides:

1h(y)dy=g(x)dx\int \frac{1}{h(y)} \, dy = \int g(x) \, dx

infoNote

📑Example: Solve the differential equation:

dydx=xy\frac{dy}{dx} = xy

Solution:

  1. Separate the variables:

1ydy=xdx\frac{1}{y} \, dy = x \, dx

  1. Integrate both sides:

1ydy=xdx\int \frac{1}{y} \, dy = \int x \, dx

lny=x22+C\ln |y| = \frac{x^2}{2} + C

Where C C is the constant of integration.

  1. Solve for yy :

y=ex22+C=eCex22y = e^{\frac{x^2}{2} + C} = e^C \cdot e^{\frac{x^2}{2}}

Since eCe^C is just another constant, let's call it C1C_1 :

y=C1ex22y = C_1 e^{\frac{x^2}{2}}

This is the general solution.

2. Second-Order Differential Equations

A second-order differential equation involves the second derivative of the unknown function:

d2ydx2+p(x)dydx+q(x)y=0\frac{d^2y}{dx^2} + p(x) \frac{dy}{dx} + q(x)y = 0

For constant coefficients, where p(x)p(x) and q(x)q(x) are constants, the general solution can be found by solving the characteristic equation.

infoNote

📑Example 2: Homogeneous Second-Order Differential Equations Consider:

d2ydx23dydx+2y=0\frac{d^2y}{dx^2} - 3\frac{dy}{dx} + 2y = 0

Solution:

  1. Find the characteristic equation:

m23m+2=0m^2 - 3m + 2 = 0

  1. Solve the quadratic equation:

(m1)(m2)=0(m - 1)(m - 2) = 0

So, m=1m = 1 and m=2m = 2 .

  1. Write the general solution: For distinct roots m1m_1 and m2m_2 , the general solution is:

y(x)=C1em1x+C2em2xy(x) = C_1 e^{m_1 x} + C_2 e^{m_2 x}

Substituting m1=1m_1 = 1 and m2=2m_2 = 2 :

y(x)=C1ex+C2e2xy(x) = C_1 e^{x} + C_2 e^{2x}

This is the general solution.

Summary

infoNote

The general solution of a differential equation represents the family of all possible solutions, typically including one or more arbitrary constants. For first-order equations, the general solution is found by integration, while for second-order equations with constant coefficients, it involves solving a characteristic equation. Understanding how to derive these solutions is essential for solving problems that model real-world phenomena in physics, engineering, and other fields.

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