Photo AI

Last Updated Sep 27, 2025

Reverse Chain Rule Simplified Revision Notes

Revision notes with simplified explanations to understand Reverse Chain Rule quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

276+ students studying

8.2.3 Reverse Chain Rule

The Reverse Chain Rule, also known as integration by substitution, is a method used to evaluate integrals where the integrand is a composite function. The idea is to reverse the process of differentiation using the chain rule, hence the name.

Steps for Using the Reverse Chain Rule:

infoNote
  1. Identify the Inner Function:
  • Look for a function inside another function. This inner function is typically what you would have differentiated in the chain rule.
  1. Substitute the Inner Function:
  • Let  u=g(x)\ u = g(x) , where  g(x)\ g(x) is the inner function.
  • Differentiate  u\ u with respect to  x\ x to find  dudx.\ \frac{du}{dx}.
  1. Rewrite the Integral:
  • Replace all occurrences of  g(x)\ g(x) with  u and dx\ u \ and \ dx with  dududx.\ \frac{du}{\frac{du}{dx}} .
  • The integral should now be in terms of  u and du\ u \ and \ du , which may simplify the integration process.
  1. Integrate with Respect to  u\ u :
  • Perform the integration with respect to  u.\ u .
  1. Substitute Back:
  • After finding the integral in terms of uu, substitute  u=g(x)\ u = g(x) back into the expression to obtain the final answer in terms of  x\ x .
infoNote

Example:

Evaluate  2xcos(x2)dx.\ \int 2x \cdot \cos(x^2) \, dx .


  1. Identify the Inner Function:
  • Here,  g(x)=x2\ g(x) = x^2 , and the derivative  g(x)=2x.\ g'(x) = 2x .

  1. Substitute:
  • Let  u=x2 ,so du=2xdx.\ u = x^2 \ , so \ du = 2x \, dx .

  1. Rewrite the Integral:
  • The integral becomes  cos(u)du.\ \int \cos(u) \, du .

  1. Integrate:
  • The integral of  cos(u) is sin(u).\ \cos(u) \ is \ \sin(u) .

  1. Substitute Back:
  • Replace  u with x2\ u \ with \ x^2 to get the final answer:  sin(x2)+C.\ \sin(x^2) + C .

More specific examples…

infoNote

Example 1: Basic u-substitution

Question:

Evaluate (3x2)(x3+1)5dx\int (3x^2)(x^3 + 1)^5 \, dx

Solution:

  1. Identify the inner function: Notice that x3+1x^3 + 1 is the inner function inside the power, and its derivative is 3x23x^2, which is also in the integrand.

  2. Let u=x3+1u = x^3 + 1 : This gives:

dudx=3x2ordu=3x2dx\frac{du}{dx} = 3x^2 \quad \text{or} \quad du = 3x^2 \, dx
  1. Rewrite the integral in terms of uu:
(3x2)(x3+1)5dx=u5du\int (3x^2)(x^3 + 1)^5 \, dx = \int u^5 \, du
  1. Integrate:
u5du=u66+C\int u^5 \, du = \frac{u^6}{6} + C
  1. Substitute back u=x3+1:u = x^3 + 1:
(x3+1)66+C\frac{(x^3 + 1)^6}{6} + C

Thus, the solution is:

(x3+1)66+C\frac{(x^3 + 1)^6}{6} + C

infoNote

Example 2: Exponential Function

Question:

Evaluate 2xex2dx\int 2xe^{x^2} \, dx.

Solution:

  1. Identify the inner function: The function inside the exponential is x2 x^2, and its derivative is 2x2x, which is in the integrand.

  2. Let u=x2u = x^2: This gives:

dudx=2xordu=2xdx\frac{du}{dx} = 2x \quad \text{or} \quad du = 2x \, dx
  1. Rewrite the integral in terms of uu:
2xex2dx=eudu\int 2xe^{x^2} \, dx = \int e^u \, du
  1. Integrate:
eudu=eu+C\int e^u \, du = e^u + C
  1. Substitute back u=x2u = x^2:
ex2+Ce^{x^2} + C

Thus, the solution is:

ex2+Ce^{x^2} + C

infoNote

Example 3: Trigonometric Function

Question:

Evaluate cos(3x)dx\int \cos(3x) \, dx.

Solution:

  1. Identify the inner function: The inner function is 3x3x, and its derivative is 33.

  2. Let u=3xu = 3x: This gives:

dudx=3ordu=3dx\frac{du}{dx} = 3 \quad \text{or} \quad du = 3 \, dx

To match the integral, divide both sides by 3:

du3=dx\frac{du}{3} = dx
  1. Rewrite the integral in terms of uu:
cos(3x)dx=cos(u)du3=13cos(u)du\int \cos(3x) \, dx = \int \cos(u) \cdot \frac{du}{3} = \frac{1}{3} \int \cos(u) \, du
  1. Integrate:
13sin(u)+C\frac{1}{3} \sin(u) + C
  1. Substitute back u=3x u = 3x:
13sin(3x)+C\frac{1}{3} \sin(3x) + C

Thus, the solution is:

13sin(3x)+C\frac{1}{3} \sin(3x) + C

infoNote

Example 4: More Complex Polynomial

Question:

Evaluate (2x+1)3(x+1)dx\int (2x + 1)^3 \cdot (x + 1) \, dx

Solution:

  1. Identify the inner function: The inner function u=x+1u = x + 1 appears inside the cubic power.

  2. Let u=x+1:u = x + 1: This gives:

dudx=1ordu=dx\frac{du}{dx} = 1 \quad \text{or} \quad du = dx
  1. Rewrite the integral: Since 2x+1=2(x+1)1=2u12x + 1 = 2(x + 1) - 1 = 2u - 1 , the integral becomes:
(2u1)3udu\int (2u - 1)^3 \cdot u \, du
  1. Expand the expression: First expand (2u1)3(2u - 1)^3 :
(2u1)3=8u312u2+6u1(2u - 1)^3 = 8u^3 - 12u^2 + 6u - 1

Now multiply by uu :

u(8u312u2+6u1)du=(8u412u3+6u2u)du\int u(8u^3 - 12u^2 + 6u - 1) \, du = \int (8u^4 - 12u^3 + 6u^2 - u) \, du
  1. Integrate each term:
8u5512u44+6u33u22+C\frac{8u^5}{5} - \frac{12u^4}{4} + \frac{6u^3}{3} - \frac{u^2}{2} + C

Simplifying:

8u553u4+2u3u22+C\frac{8u^5}{5} - 3u^4 + 2u^3 - \frac{u^2}{2} + C
  1. Substitute back u=x+1u = x + 1:
8(x+1)553(x+1)4+2(x+1)3(x+1)22+C\frac{8(x + 1)^5}{5} - 3(x + 1)^4 + 2(x + 1)^3 - \frac{(x + 1)^2}{2} + C
Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master Reverse Chain Rule

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

120 flashcards

Flashcards on Reverse Chain Rule

Revise key concepts with interactive flashcards.

Try Maths Pure Flashcards

12 quizzes

Quizzes on Reverse Chain Rule

Test your knowledge with fun and engaging quizzes.

Try Maths Pure Quizzes

11 questions

Exam questions on Reverse Chain Rule

Boost your confidence with real exam questions.

Try Maths Pure Questions

27 exams created

Exam Builder on Reverse Chain Rule

Create custom exams across topics for better practice!

Try Maths Pure exam builder

18 papers

Past Papers on Reverse Chain Rule

Practice past papers to reinforce exam experience.

Try Maths Pure Past Papers

Other Revision Notes related to Reverse Chain Rule you should explore

Discover More Revision Notes Related to Reverse Chain Rule to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Further Integration

Integration as the limit of a sum

user avatar
user avatar
user avatar
user avatar
user avatar

463+ studying

182KViews

96%

114 rated

Further Integration

Integrating Other Functions (Trig, ln & e etc)

user avatar
user avatar
user avatar
user avatar
user avatar

493+ studying

185KViews

96%

114 rated

Further Integration

f'(x)/f(x)

user avatar
user avatar
user avatar
user avatar
user avatar

329+ studying

200KViews

96%

114 rated

Further Integration

Substitution (Reverse Chain Rule)

user avatar
user avatar
user avatar
user avatar
user avatar

445+ studying

180KViews
Load more notes

Join 500,000+ A-Level students using SimpleStudy...

Join Thousands of A-Level Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered