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Coulomb’s law Simplified Revision Notes

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7.3.1 Coulomb's law

Definition

Coulomb's Law states that the force between two point charges in a vacuum is:

  • Directly proportional to the product of the two charges.
  • Inversely proportional to the square of the distance between them. The mathematical expression for Coulomb's law is:
F=14πε0Q1Q2r2F = \frac{1}{4\pi \varepsilon_0} \frac{Q_1 Q_2}{r^2}

Where:

  • F is the force between the charges,
  • ε0\varepsilon_0 is the permittivity of free space,
  • Q1Q_1 and Q2Q_2 are the charges,
  • rr is the distance between the centres of the charges.
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infoNote

Important Notes:

  • Air can be approximated as a vacuum for the purposes of calculations with Coulomb's law.

  • For a spherical charge distribution, the charge can be considered to act from the centre of the sphere. Force Direction:

  • If both charges are of the same sign, the force is repulsive.

  • If the charges have opposite signs, the force is attractive.

Comparing Electrostatic and Gravitational Forces

infoNote

The electrostatic force between subatomic particles (like protons and electrons) is generally much stronger than the gravitational force acting between them. This difference is due to the relatively small masses and larger charges of these particles. Here's a calculation example for illustration:

Consider two protons, 2 pm (or 2 × 10⁻¹² m) apart.

  1. Gravitational Force Calculation:
F=Gm1m2r2=6.67×1011×(1.67×1027)2(2×1012)2=:highlight[4.65×1041N]F = \frac{G m_1 m_2}{r^2} = \frac{6.67 \times 10^{-11} \times (1.67 \times 10^{-27})^2}{(2 \times 10^{-12})^2} = :highlight[4.65 \times 10^{-41} \, \text{N}]
  1. Electrostatic Force Calculation:
F=14πε0Q1Q2r2=14π×8.85×1012(1.6×1019)2(2×1012)2=:highlight[5.75×105N]F = \frac{1}{4 \pi \varepsilon_0} \frac{Q_1 Q_2}{r^2} = \frac{1}{4 \pi \times 8.85 \times 10^{-12}} \frac{(1.6 \times 10^{-19})^2}{(2 \times 10^{-12})^2} = :highlight[5.75 \times 10^{-5} \, \text{N}]
  1. Ratio of Electrostatic Force to Gravitational Force:
FelectrostaticFgravitational=5.75×1054.65×1041=:highlight[1.24×1036]\frac{F_{\text{electrostatic}}}{F_{\text{gravitational}}} = \frac{5.75 \times 10^{-5}}{4.65 \times 10^{-41}} = :highlight[1.24 \times 10^{36}]

Conclusion:

The electrostatic force between two protons is approximately 1.24 × 10³⁶ times stronger than the gravitational force. This significant difference is why electrostatic forces dominate interactions at the atomic and subatomic levels.

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