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Simplex Algorithm - Slack Variables & Initial Tableau Simplified Revision Notes

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12.3.1 Simplex Algorithm - Slack Variables & Initial Tableau

Introduction

The Simplex algorithm is a systematic method for solving linear programming problems. It is commonly used for maximising or minimising an objective function subject to constraints. This note focuses on the initial steps of the algorithm:

  1. Introducing slack variables to convert inequalities into equations.
  2. Setting up the initial tableau for maximisation or minimisation problems.

Key Concepts

Slack Variables

Slack variables are added to constraints of the form \leq to convert them into equations. For example:

x+y6x+y+s1=6,s10x + y \leq 6 \quad \Rightarrow \quad x + y + s_1 = 6, \quad s_1 \geq 0

where s1s_1 is the slack variable representing unused capacity.

Initial Simplex Tableau

The problem is represented in tabular form, with rows for the constraints and columns for the variables:

  • Decision variables (x1,x2,x_1, x_2, \dots)
  • Slack variables (s1,s2,s_1, s_2, \dots)
  • Objective function (ZZ) Each row represents a constraint, and the last row represents the negative of the objective function.

Setting Up the Initial Tableau

Problem Structure

1. Maximisation Problem:

Maximise Z=c1x1+c2x2++cnxnZ = c_1x_1 + c_2x_2 + \dots + c_nx_n

Subject to:

a11x1+a12x2++s1=b1a_{11}x_1 + a_{12}x_2 + \dots + s_1 = b_1 a21x1+a22x2++s2=b2a_{21}x_1 + a_{22}x_2 + \dots + s_2 = b_2 x1,x2,,s1,s20x_1, x_2, \dots, s_1, s_2 \geq 0

2. Initial Tableau:

The tableau has:

Columns for x1,x2,x_1, x_2, \dots, slack variables (s1,s2,s_1, s_2, \dots), and ZZ

Rows for each constraint and the objective function.

Worked Examples

infoNote

Example 1: Maximising an Objective Function


Problem

Maximise:

Z=3x1+2x2Z = 3x_1 + 2x_2

Subject to:

  1. x1+x24x_1 + x_2 \leq 4
  2. 2x1+x262x_1 + x_2 \leq 6
  3. x1,x20x_1, x_2 \geq 0

Step 1: Add Slack Variables

Convert each inequality into an equation:

x1+x2+s1=4x_1 + x_2 + s_1 = 42x1+x2+s2=62x_1 + x_2 + s_2 = 6

where s1,s20s_1, s_2 \geq 0


Step 2: Set Up the Initial Tableau

Basic Variablex1x2s1s2ZRHSs1111004s2210106Z320010\begin{array}{c|ccccc|c} \text{Basic Variable} & x_1 & x_2 & s_1 & s_2 & Z & \text{RHS} \\ \hline s_1 & 1 & 1 & 1 & 0 & 0 & 4 \\ s_2 & 2 & 1 & 0 & 1 & 0 & 6 \\ \hline Z & -3 & -2 & 0 & 0 & 1 & 0 \\ \end{array}
  • Basic Variable: Indicates which variable is currently in the solution (initially slack variables).
  • RHS: Right-hand side of the equations.
  • The ZZ-row represents the negative of the objective function.

Step 3: Interpret the Tableau

The current solution is x1=0,x2=0,s1=4,s2=6x_1 = 0, x_2 = 0, s_1 = 4, s_2 = 6, giving Z=0Z = 0

ZZ-row negative values (3,2)(-3, -2) indicate potential for improvement.

infoNote

Example 2: Minimising an Objective Function


Problem

Minimise:

Z=4x1+3x2Z = 4x_1 + 3x_2

Subject to:

  1. x1+2x28x_1 + 2x_2 \leq 8
  2. 2x1+x2102x_1 + x_2 \leq 10
  3. x1,x20x_1, x_2 \geq 0

Step 1: Add Slack Variables

x1+2x2+s1=8x_1 + 2x_2 + s_1 = 82x1+x2+s2=102x_1 + x_2 + s_2 = 10

where s1,s20s_1, s_2 \geq 0


Step 2: Set Up the Initial Tableau

Basic Variablex1x2s1s2ZRHSs1121008s22101010Z430010\begin{array}{c|ccccc|c} \text{Basic Variable} & x_1 & x_2 & s_1 & s_2 & Z & \text{RHS} \\ \hline s_1 & 1 & 2 & 1 & 0 & 0 & 8 \\ s_2 & 2 & 1 & 0 & 1 & 0 & 10 \\ \hline Z & 4 & 3 & 0 & 0 & 1 & 0 \\ \end{array}

Note Summary

infoNote

Common Mistakes

  1. Forgetting slack variables: Omitting slack variables results in incorrect equations.
  2. Incorrect objective function: Failing to convert the objective function to a negative form for the tableau.
  3. Mixing maximization and minimization methods: Ensure the tableau reflects the correct goal.
  4. Arithmetic errors: Mistakes in setting up coefficients for constraints.
  5. Misinterpreting the tableau: Confusion about the role of the row and RHS values.
infoNote

Key Formulas

  1. Slack Variable for \leq Constraints:
a1x1+a2x2ba1x1+a2x2+s=b,s0a_1x_1 + a_2x_2 \leq b \quad \Rightarrow \quad a_1x_1 + a_2x_2 + s = b, \quad s \geq 0
  1. Initial Objective Function Row:
Z=c1x1+c2x2Zc1x1c2x2=0Z = c_1x_1 + c_2x_2 \quad \Rightarrow \quad Z - c_1x_1 - c_2x_2 = 0
  1. Initial Tableau: Set up rows for constraints and the ZZ-row, using slack variables for each \leq constraint.
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