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Kinetic & Potential Energy Simplified Revision Notes

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14.1.1 Kinetic & Potential Energy

Introduction

Kinetic and potential energy are two key forms of mechanical energy. These concepts are fundamental to understanding motion and energy transformations. In this note, we focus on:

  1. Kinetic Energy (KE): The energy of motion.
  2. Potential Energy (PE): The energy due to position relative to a reference level. We will use these ideas to solve problems involving motion under gravity, often on an inclined plane.

Kinetic Energy (KE)

The kinetic energy of an object of mass mm moving with velocity vv is given by:

KE=12mv2KE = \frac{1}{2}mv^2

where:

  • mm is the mass (kg\text{kg})
  • vv is the velocity (ms1\text{ms}^{-1}) Kinetic energy is always non-negative and depends on the square of the speed.

Potential Energy (PE)

The potential energy of an object of mass mm at height hh above a reference point is:

PE=mghPE = mgh

where:

  • gg is the acceleration due to gravity (:highlight[9.8]ms2:highlight[9.8] \, \text{ms}^{-2})
  • hh is the height (m\text{m}) Potential energy depends on the relative position of the object.

Worked Examples

infoNote

Example 1: Kinetic Energy of a Moving Object


Problem

A ball of mass :highlight[0.5]kg:highlight[0.5] \, \text{kg} is thrown with a velocity of :highlight[8]ms1:highlight[8] \, \text{ms}^{-1}

Find its kinetic energy.


Step 1: Use the formula for kinetic energy:

KE=12mv2KE = \frac{1}{2}mv^2

Step 2: Substitute the values (m=0.5kg,v=8ms1m = 0.5 \, \text{kg}, v = 8 \, \text{ms}^{-1})

KE=12(0.5)(8)2=0.25(64)=16JKE = \frac{1}{2}(0.5)(8)^2 = 0.25(64) = 16 \, \text{J}

Final Answer:

The kinetic energy is 16 J

Note Summary

infoNote

Common Mistakes

  1. Forgetting starting velocity: Include initial kinetic energy if the object starts with a velocity.
  2. Mixing velocity and speed: Kinetic energy depends on speed (magnitude), not direction.
  3. Omitting units: Always include the correct units for energy (J\text{J})
infoNote

Key Formulas

  1. Kinetic Energy:
KE=12mv2KE = \frac{1}{2}mv^2
  1. Potential Energy:
PE=mghPE = mgh
  1. Conservation of Mechanical Energy:
KE+PE=constantKE + PE = \text{constant}
  1. Height on an Incline:
h=dsinθh = d \sin \theta
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