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SUVAT in 1D Simplified Revision Notes

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2.3.2 SUVAT in 1D

Kinematics with Constant Acceleration

infoNote

There are a number of equations of motion:

v=u+atv = u + ats=(u+v)2×ts = \frac{(u + v)}{2} \times ts=ut+12at2s = ut + \frac{1}{2}at^2v2=u2+2asv^2 = u^2 + 2ass=vt12at2s = vt - \frac{1}{2}at^2

Where:

  • ss is displacement
  • uu is initial velocity
  • vv is final velocity
  • aa is acceleration
  • tt is time

infoNote

Example 1:

A particle is moving with an initial velocity equal to 2 ms⁻¹ in a positive direction. Its final velocity after traveling a distance of 20 m is 23 ms⁻¹. Assuming constant acceleration, find the acceleration of the particle.

Given:

  • S = 20 m
  • U = 2 ms⁻¹
  • V = 23 ms⁻¹
  • a = ? Using the equation:
v2=u2+2asv^2 = u^2 + 2as

Substituting the values:

232=22+2a(20)23^2 = 2^2 + 2a(20)

Simplifying:

529=4+40a529 = 4 + 40a525=40a525 = 40aa=:success[13.125ms2]a = :success[13.125 ms⁻²]

infoNote

Example 2:

A particle is traveling with an initial velocity of 16 ms⁻¹ and over a distance of 350 m, accelerates at a rate of 8 ms⁻². Find the time taken to travel the 350 m journey.

Given:

  • S = 350 m
  • U = 16 ms⁻¹
  • a = 8 ms⁻²
  • t = ? Using the equation:
s=ut+12at2s = ut + \frac{1}{2}at^2

Substituting the values:

350=16t+12(8)t2350 = 16t + \frac{1}{2}(8)t^2

Simplifying:

350=16t+4t2350 = 16t + 4t^24t2+16t350=04t^2 + 16t - 350 = 0

Using the quadratic formula, the time tt is approximately 7.57 s.


infoNote

Example: 3

A particle accelerates uniformly. Initially, it has a speed of 6 ms⁻¹, then after 12 seconds, it has a speed of 6 ms⁻¹ in the opposite direction. Find the acceleration of the particle.

Given:

  • U=:highlight[6ms1]U = :highlight[6 ms⁻¹]
  • V=:highlight[6ms1]V = :highlight[-6 ms⁻¹]
  • a=?a = ?
  • t=:highlight[12s]t = :highlight[12 s] Using the equation:
v=u+atv = u + at

Substituting the values:

6=6+a(12)-6 = 6 + a(12)

Simplifying:

66=12a    12=12a    a=:success[1ms2]-6 - 6 = 12a \implies -12 = 12a \implies a = :success[-1 ms⁻²]

Note: A negative acceleration is called deceleration.


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