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Deriving the SUVAT Equations Simplified Revision Notes

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2.3.1 Deriving the SUVAT Equations

Derivation of SUVAT Equations

infoNote

The SUVAT equations are used in mechanics to describe the motion of an object under constant acceleration. They relate five key variables:

  • ss: displacement
  • uu: initial velocity
  • vv: final velocity
  • aa: acceleration
  • tt: time
infoNote

The equations are:

v=u+atv = u + ats=(u+v)2ts = \frac{(u + v)}{2} ts=ut+12at2s = ut + \frac{1}{2} at^2v2=u2+2asv^2 = u^2 + 2ass=vt12at2s = vt - \frac{1}{2} at^2
infoNote

These equations apply only when acceleration is constant and are useful for solving problems involving linear motion, such as finding the distance travelled or the time taken to reach a certain velocity.


The SUVAT equations can be derived using a velocity-time vtv-t graph.

image

1. First Equation: v=u+atv = u + at

infoNote

Graph**:**

  • The vertical axis represents velocity v) in meters per second m/s).

  • The horizontal axis represents time t) in seconds.

  • The initial velocity is uu.

  • The final velocity is vv. Gradient**:**

  • The gradient of the graph represents acceleration aa.

a=vuta = \frac{v - u}{t}

Rearranging**:**

vu=atv - u = atv=u+atv = u + at

2. Second Equation: s=(u+v)2×ts = \frac{(u + v)}{2} \times t

infoNote

Area Under the Graph:

  • The area under the graph represents the displacement s). Trapezium Area Formula:
s=(u+v)2×ts = \frac{(u + v)}{2} \times t
  • Where s is the area between the graph and the x-axis.

3. Third Equation: s=ut+12at2s = ut + \frac{1}{2}at^2

infoNote

Derivation**:**

  • Consider the area between the line and the x-axis to be the sum of a rectangle and a triangle. Equation**:**
s=ut+12(vu)ts = ut + \frac{1}{2}(v - u)t

Substituting vu=atv - u = at (from the first equation):

s=ut+12at×t=ut+12at2s = ut + \frac{1}{2}at \times t = ut + \frac{1}{2}at^2

4. Fourth Equation: s=vt12at2s = vt - \frac{1}{2}at^2

infoNote

Derivation**:**

  • Consider the area to be a rectangle with a triangle subtracted. Equation**:**
s=vt12(vu)ts = vt - \frac{1}{2}(v - u)t

Substituting vu=atv - u = at:

s=vt12at×t=vt12at2s = vt - \frac{1}{2}at \times t = vt - \frac{1}{2}at^2

5. Fifth SUVAT Equation: v2=u2+2asv^2 = u^2 + 2as

infoNote

Starting from the equation:

v=u+atv = u + at

Square both sides:

v2=(u+at)2=u2+2uat+a2t2v^2 = (u + at)^2 = u^2 + 2uat + a^2t^2

Recognize that:

v2=u2+2a(ut+12at2)v^2 = u^2 + 2a(ut + \frac{1}{2}at^2)

where s=ut+12at2s = ut + \frac{1}{2}at^2.

Thus, simplifying gives:

v2=u2+2asv^2 = u^2 + 2as
infoNote

The SUVAT equations are provided in the formula book, but the specification outlines that you should be able to 'understand, use and derive the formulae for constant acceleration for motion in a straight line'

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