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Expanding Brackets Simplified Revision Notes

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2.5.1 Expanding Brackets

Expanding brackets is a fundamental algebraic technique used to simplify expressions by removing parentheses (brackets) and combining like terms. This skill is essential for solving equations, simplifying expressions, and working with polynomials.

1. Expanding a Single Bracket

When you expand a single bracket, you distribute the term outside the bracket to each term inside the bracket.

General Form: a(b+c)=ab+aca(b + c) = ab + ac

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Example: 3(x+4)=3×x+3×4=3x+123(x + 4) = 3 \times x + 3 \times 4 = 3x + 12

2. Expanding Double Brackets

Expanding double brackets involves multiplying two binomials (expressions with two terms). The most common method is the FOIL method (First, Outside, Inside, Last).

General Form: (a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd

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FOIL Method:

  • First: Multiply the first terms from each bracket.
  • Outside: Multiply the outer terms.
  • Inside: Multiply the inner terms.
  • Last: Multiply the last terms.
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Example: (x+2)(x+3)(x + 2)(x + 3)

  • First:  x×x=x2\ x \times x = x^2
  • Outside:  x×3=3x\ x \times 3 = 3x
  • Inside:  2×x=2x\ 2 \times x = 2x
  • Last:  2×3=6\ 2 \times 3 = 6 Combine the results: x2+3x+2x+6=x2+5x+6x^2 + 3x + 2x + 6 = x^2 + 5x + 6

3. Expanding with Negative Signs

When dealing with negative signs, be careful with the distribution to ensure correct signs in the expanded expression.

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Example: (2x3)(x+4)(2x - 3)(x + 4)

  • First:  2x×x=2x2\ 2x \times x = 2x^2
  • Outside:  2x×4=8x\ 2x \times 4 = 8x
  • Inside:  3×x=3x\ -3 \times x = -3x
  • Last:  3×4=12\ -3 \times 4 = -12 Combine the results: 2x2+8x3x12=2x2+5x122x^2 + 8x - 3x - 12 = 2x^2 + 5x - 12

4. Expanding with More Than Two Brackets

When expanding more than two brackets, expand two brackets first, then multiply the result by the remaining bracket(s).

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Example: (x+1)(x2)(x+3)(x + 1)(x - 2)(x + 3)

  • First, expand  (x+1)(x2)=x2x2.\ (x + 1)(x - 2) = x^2 - x - 2 .
  • Then, multiply this result by  (x+3)\ (x + 3) : (x2x2)(x+3)=x3+3x2x23x2x6=x3+2x25x6(x^2 - x - 2)(x + 3) = x^3 + 3x^2 - x^2 - 3x - 2x - 6 = x^3 + 2x^2 - 5x - 6

Summary:

  • Single Bracket: Distribute the outer term across the inner terms.
  • Double Brackets: Use the FOIL method to ensure all terms are multiplied correctly.
  • Negative Signs: Pay close attention to signs when distributing.
  • Multiple Brackets: Expand in pairs, then combine results.
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