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Basic Coordinate Geometry Simplified Revision Notes

Revision notes with simplified explanations to understand Basic Coordinate Geometry quickly and effectively.

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3.1.1 Basic Coordinate Geometry

Basic coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system. It allows us to describe geometric shapes, such as lines, circles, and polygons, algebraically using equations. Here are some fundamental concepts and techniques:

1. The Coordinate Plane

The coordinate plane, also known as the Cartesian plane, is a two-dimensional plane defined by two perpendicular axes: the horizontal  x\ x -axis and the vertical  y\ y -axis. The point where these axes intersect is called the origin, denoted as  (0,0)\ (0, 0) .

Each point on the plane is represented by an ordered pair  (x,y)\ (x, y) , where:

  •  x\ x is the horizontal distance from the origin (positive to the right, negative to the left).
  •  y\ y is the vertical distance from the origin (positive upward, negative downward).

2. Distance Between Two Points

The distance between two points  A(x1,y1)\ A(x_1, y_1) and  B(x2,y2)\ B(x_2, y_2) on the coordinate plane is given by the distance formula:

 Distance=(x2x1)2+(y2y1)2\ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

infoNote

Example: Find the distance between  A(1,2) and B(4,6).\ A(1, 2) \ and \ B(4, 6) .

Solution:

Distance=(41)2+(62)2=32+42=9+16=25=:success[5]\text{Distance} = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = :success[5]

3. Midpoint of a Line Segment

The midpoint of a line segment connecting two points  A(x1,y1)\ A(x_1, y_1) and  B(x2,y2)\ B(x_2, y_2) is the point exactly halfway between them. It is given by the midpoint formula:

Midpoint=(x1+x22,y1+y22)\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

infoNote

Example: Find the midpoint of the line segment joining  A(1,2)\ A(1, 2) and  B(4,6).\ B(4, 6) .

Solution:

Midpoint=(1+42,2+62)=(52,82)=:success[(2.5,4)]\text{Midpoint} = \left( \frac{1 + 4}{2}, \frac{2 + 6}{2} \right) = \left( \frac{5}{2}, \frac{8}{2} \right) = :success[\left( 2.5, 4 \right)]

4. Slope of a Line

The slope of a line is a measure of its steepness and is defined as the ratio of the change in the y\ y-coordinate to the change in the  x\ x -coordinate between two points on the line. If  A(x1,y1)\ A(x_1, y_1) and  B(x2,y2)\ B(x_2, y_2) are two points on the line, the slope m\ m is:

m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

  • A positive slope indicates the line rises as it moves from left to right.
  • A negative slope indicates the line falls as it moves from left to right.
  • A slope of 00 indicates a horizontal line.
  • An undefined slope (division by 00) indicates a vertical line.
infoNote

Example: Find the slope of the line passing through  A(1,2)\ A(1, 2) and  B(4,6).\ B(4, 6) .

Solution:

m=6241=:success[43]m = \frac{6 - 2}{4 - 1} = :success[\frac{4}{3}]

5. Equation of a Line

The equation of a line can be expressed in several forms, with the most common being the slope-intercept form and the point-slope form.

Slope-Intercept Form

The slope-intercept form of the equation of a line is:

y=mx+cy = mx + c

  •  m\ m is the slope of the line.
  •  c\ c is the y\ y-intercept (the point where the line crosses the  y\ y -axis).
infoNote

Example: Find the equation of a line with a slope of  43\ \frac{4}{3} and a  y\ y -intercept of 11.

Solution:

:success[y=43x+1]:success[y = \frac{4}{3}x + 1]

Point-Slope Form

The point-slope form of the equation of a line passing through a point  (x1,y1)\ (x_1, y_1) with slope  m\ m is:

yy1=m(xx1)y - y_1 = m(x - x_1)

infoNote

Example: Find the equation of the line passing through  (2,3)\ (2, 3) with a slope of 22.

Solution:

y3=2(x2)y - 3 = 2(x - 2)

Expanding this:

:success[y=2x1]:success[y = 2x - 1]

6. Parallel and Perpendicular Lines

  • Parallel Lines: Two lines are parallel if they have the same slope, i.e.,  m1=m2.\ m_1 = m_2 .
  • Perpendicular Lines: Two lines are perpendicular if the product of their slopes is  1\ -1, i.e.,  m1×m2=1.\ m_1 \times m_2 = -1 .
infoNote

Example: If a line has a slope of  23,\ \frac{2}{3} , what is the slope of a line perpendicular to it?

Solution:

The slope of the perpendicular line is the negative reciprocal: :success[m=32]:success[m = -\frac{3}{2}]

Practice Problem:

infoNote

Find the equation of the line that passes through the point  (1,2)\ (1, 2) and is parallel to the line  y=3x+4.\ y = 3x + 4 .

infoNote

Solution: Since the lines are parallel, they share the same slope  m=3\ m = 3 . Using the point-slope form:

y2=3(x1)y - 2 = 3(x - 1)

Simplify:

y=3x3+2=3x1y = 3x - 3 + 2 = 3x - 1

So, the equation is  :success[y=3x1].\ :success[y = 3x - 1] .

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