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5.5.4 Inverse Trig Functions

Inverse trigonometric functions are the inverse operations of the basic trigonometric functions (sine, cosine, tangent, etc.). They are used to find the angle that corresponds to a given trigonometric value. These functions are important in many areas of mathematics, including calculus, geometry, and solving trigonometric equations.

1. Definitions of Inverse Trigonometric Functions:

  • Inverse Sine sin1x or (arcsinx)\sin^{-1} x\ or \ (arcsin x): sin1x=θif and only ifsinθ=x\sin^{-1} x = \theta \quad \text{if and only if} \quad \sin \theta = x
  • The inverse sine function returns the angle whose sine is xx.
  • Domain: -1 ≤ x ≤ 1
  • Range: -π/2 ≤ θ ≤ π/2 (or -90° ≤ θ ≤ 90°)
  • Inverse Cosine (cos1x or (arccosx)\cos^{-1} x\ or \ (arccos x): cos1x=θif and only ifcosθ=x\cos^{-1} x = \theta \quad \text{if and only if} \quad \cos \theta = x
  • The inverse cosine function returns the angle whose cosine is xx.
  • Domain: -1 ≤ x ≤ 1
  • Range: 0 ≤ θ ≤ π (or 0° ≤ θ ≤ 180°)
  • Inverse Tangent (tan1x or (arctanx)\tan^{-1} x\ or \ (\arctan x): tan1x=θif and only iftanθ=x\tan^{-1} x = \theta \quad \text{if and only if} \quad \tan \theta = x
  • The inverse tangent function returns the angle whose tangent is xx.
  • Domain: -∞ < x < ∞
  • Range: -π/2 < θ < π/2 (or -90° < θ < 90°)
  • Inverse Cosecant (csc1x or arccscx\csc^{-1} x\ or\ arccsc x): csc1x=θif and only ifcscθ=x\csc^{-1} x = \theta \quad \text{if and only if} \quad \csc \theta = x
  • Domain: x ≤ -1 or x ≥ 1
  • Range: -π/2 ≤ θ ≤ π/2, θ ≠ 0 (or -90° ≤ θ ≤ 90°, θ ≠ 0°)
  • Inverse Secant (sec1x or arcsecx(\sec^{-1} x\ or \ arcsec x): sec1x=θif and only ifsecθ=x\sec^{-1} x = \theta \quad \text{if and only if} \quad \sec \theta = x
  • Domain: x ≤ -1 or x ≥ 1
  • Range: 0 ≤ θ ≤ π, θ ≠ π/2 (or 0° ≤ θ ≤ 180°, θ ≠ 90°)
  • Inverse Cotangent (cot1x or arccotx)\cot^{-1} x\ or \ arccot x)): cot1x=θif and only ifcotθ=x\cot^{-1} x = \theta \quad \text{if and only if} \quad \cot \theta = x
  • Domain: -∞ < x < ∞
  • Range: 0 < θ < π (or 0° < θ < 180°)

2. Graphs of Inverse Trigonometric Functions:

  • Inverse Sine  (arcsinx):\ (\arcsin x):
  • The graph of y=arcsinxy = \arcsin x is a smooth curve that starts at (-1, -π/2) and ends at (1, π/2). image
image
  • Inverse Cosine (arccosx\arccos x):

  • The graph of y=arccosxy = \arccos x is a decreasing curve that starts at (-1, π) and ends at (1, 0).

  • Inverse Tangent (arctanx\arctan x):

  • The graph of y = arctanx\arctan x is an increasing curve that approaches horizontal asymptotes at y = -π/2 and y = π/2 as x approaches negative and positive infinity, respectively.

    image

3. Key Properties and Identities:

  • Inverse Function Property: sin(arcsinx)=x,cos(arccosx)=x,tan(arctanx)=x\sin(\arcsin x) = x, \quad \cos(\arccos x) = x, \quad \tan(\arctan x) = x These are true for all x within the domain of the inverse function.
  • Composite Function Property: arcsin(sinθ)=θforπ2θπ2\arcsin(\sin \theta) = \theta \quad \text{for} \quad -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2} arccos(cosθ)=θfor0θπ\arccos(\cos \theta) = \theta \quad \text{for} \quad 0 \leq \theta \leq \pi arctan(tanθ)=θforπ2<θ<π2\arctan(\tan \theta) = \theta \quad \text{for} \quad -\frac{\pi}{2} < \theta < \frac{\pi}{2}
  • Pythagorean Identity: arcsinx+arccosx=π2\arcsin x + \arccos x = \frac{\pi}{2}
    • This identity shows the relationship between the inverse sine and inverse cosine functions.

4. Example Problems Using Inverse Trigonometric Functions:

infoNote

Example 1: Solve sin1(12)\sin^{-1} \left (\frac{1}{2}\right).

  • Solution: sin1(12)=θwheresinθ=12\sin^{-1} \left(\frac{1}{2}\right) = \theta \quad \text{where} \quad \sin \theta = \frac{1}{2} The angle θ = π/6 (or 30°) is the solution because sin30=12.\sin 30^\circ = \frac{1}{2}.
infoNote

Example 2: Solve cos1(32)\cos^{-1} \left(-\frac{\sqrt{3}}{2}\right).

  • Solution: cos1(32)=θwherecosθ=32\cos^{-1} \left(-\frac{\sqrt{3}}{2}\right) = \theta \quad \text{where} \quad \cos \theta = -\frac{\sqrt{3}}{2} The angle θ = 5π/6 (or 150°) is the solution because cos150=32\cos 150^\circ = -\frac{\sqrt{3}}{2}.
infoNote

Example 3: Simplify arctan(1).\arctan(1).

  • Solution: arctan(1)=θwheretanθ=1\arctan(1) = \theta \quad \text{where} \quad \tan \theta = 1 The angle θ = π/4 (or 45°) is the solution because tan45=1\tan 45^\circ = 1.

Summary:

  • Inverse trigonometric functions allow you to find angles from given trigonometric values.
  • These functions have specific domains and ranges, which correspond to the possible values of the angle.
  • Understanding the graphs, properties, and key identities of these functions is crucial for solving trigonometric equations and simplifying expressions involving angles.

Inverse Trig Functions

  • Only 1-to-1 functions have inverses.
y=sin(x)y=cos(x)y=tan(x)\begin{align*} y &= \sin(x) \\ y &= \cos(x) \\ y &= \tan(x) \end{align*} image
  • As they stand, these functions are not 1 to 1, therefore do not have an inverse. We must restrict the domain of these functions for an inverse to exist.
y=sin(x)y = \sin(x) π2xπ2-\frac{\pi}{2} \leq x \leq \frac{\pi}{2} image
  • This version of the sine function when its domain is restricted to -π/2 ≤ x ≤ π/2 is 1 to 1, so has an inverse.
y=sin1(x)y=arcsin(x)1x1\begin{align*} y &= \sin^{-1}(x) \\ y &= \arcsin(x) \\ -1 &\leq x \leq 1 \end{align*}
  • Note: The domain of the inverse function is the range of the original.

    image
  • To draw an inverse trig function, we reflect the original function through y = x.

    • (Hint: Look at the key points of the original graph and swap x and y coordinates.)

y=cosxis 1-to-1 between0xπy = \cos x \quad \text{is 1-to-1 between}\\ \quad 0 \leq x \leq \pi image y=cos1(x)y=arccos(x)1x1\begin{align*} y &= \cos^{-1}(x) \\ y &= \arccos(x) \\ -1 &\leq x \leq 1 \end{align*} image

Graph description:

  • The first graph shows y=cosxy = \cos x between 0 and π, depicting the cosine curve restricted to one period.
  • The second graph depicts y=cos1(x) or y=arccos(x)y = \cos^{-1}(x)\ or\ y = \arccos(x), which is the inverse function of cosx\cos x, showing the range from (-1, π) to (1, 0).

y=tanxis 1-to-1 betweenπ2xπ2y = \tan x \quad \text{is 1-to-1 between} \quad -\frac{\pi}{2} \leq x \leq \frac{\pi}{2} image image y=tan1(x)y=arctan(x)xR\begin{align*} y &= \tan^{-1}(x) \\ y &= \arctan(x) \\ x &\in \mathbb{R} \end{align*}

Graph description:

  • The third graph shows the function y=tanxy = \tan x between -π/2 and π/2, illustrating the tangent function's behaviour within these limits.
  • The fourth graph displays y=tan1(x) or y=arctan(x)y = \tan^{-1}(x)\ or\ y = \arctan(x), indicating the tangent's inverse function over all real numbers.

lightbulbExample

Example Problem: e.g. Solve arcsin(x)=π4\arcsin(x) = \frac{\pi}{4}.

Hint: Perform the inverse operation of arcsin\arcsin to both sides.

sin(arcsin(x))=sin(π4)    x=22\sin(\arcsin(x)) = \sin\left(\frac{\pi}{4}\right) \implies x = \frac{\sqrt{2}}{2}

Recap of Solving Trig Equations

lightbulbExample

Example Problem: e.g. Solve sinx=0.2\sin x = 0.2

Domain: 0x2π0 \leq x \leq 2\pi

x=arcsin(0.2)0.2014x = \arcsin(0.2) \approx 0.2014 image

Graph Description:

  • The graph shows the sine function, y=sinxy = \sin x, with marked intersections at x = 0.2014 and another at π - 0.2014.
  • The first intersection at 0.2014 is where sinx=0.2\sin x = 0.2.
  • The second intersection at π - 0.2014 ≈ 2.940 is where sinx=0.2\sin x = 0.2 again.
x=0.2014,π0.2014x = 0.2014, \, \pi - 0.2014 x=0.2014,2.940x = 0.2014, \, 2.940
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