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Half Equations in Electrolysis Simplified Revision Notes

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4.3.6 Half Equations in Electrolysis

infoNote

In electrolysis, the chemical reactions that occur at each electrode can be described by half equations. These equations represent the oxidation or reduction processes happening at the anode and cathode, respectively. Each half equation shows the movement of electrons and the conversion of ions into their elemental forms.

lightbulbExample

Example: Electrolysis of Aluminium Oxide (Al₂O₃) Let's consider the electrolysis of aluminium oxide (bauxite), a key step in extracting aluminium. The overall reaction during the electrolysis of molten aluminium oxide is:

\ce2Al2O3(l)4Al(s)+3O2(g)\ce2Al_2O_3(l)→4Al(s)+3O_2(g)

However, this overall reaction is the result of separate half-reactions that occur at the cathode (reduction) and the anode (oxidation).

infoNote

Half Equations at the Electrodes

  1. At the Cathode (Reduction Reaction):
  • Aluminium ions \ce(Al3+)\ce(Al^3+) are attracted to the cathode, where they gain electrons to form aluminium metal.

  • The half equation for this reduction is: \ceAl3++3eAl(l)\ce{Al3+ +3e^−→Al(l)}

  • Here, the aluminium ion gains three electrons (3e−) to become neutral aluminium (Al)(Al).

  1. At the Anode (Oxidation Reaction):
  • Oxide ions (O2)(O2−) are attracted to the anode, where they lose electrons to form oxygen gas.
  • The half equation for this oxidation is: \ce2O2O2(g)+4e\ce2O^2−→O2(g)+4e^−
  • In this reaction, two oxide ions each lose two electrons, combining to form one molecule of oxygen gas (O2)(O2) and releasing four electrons (4e−).

Balancing Charges in Half Equations

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To ensure a half equation is correctly written, it's important to verify that the charges are balanced on both sides of the equation. In the examples above:

  • In the reduction half equation for aluminium, the charge on the left side is +3 (from \ceAl3+\ce Al3+), and the charge on the right side is 0 (Al)(Al). The electrons (3e)(3e−) balance this charge.
  • In the oxidation half equation for oxygen, the total charge on the left side is −4 (from two O2O2− ions), and the charge on the right side is 0 for the oxygen gas (O2)(O2) plus −4 from the four electrons released (4e)(4e−).

Importance of Half Equations

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Half equations are essential for understanding the detailed process of electrolysis. They allow us to see exactly what is happening at each electrode:

  • Reduction occurs at the cathode, where ions gain electrons.
  • Oxidation occurs at the anode, where ions lose electrons. By breaking down the overall electrolytic process into these half equations, chemists can better understand and predict the outcomes of electrolysis in various chemical systems. This understanding is crucial in industries that rely on electrolysis, such as metal extraction, electroplating, and the production of chemicals like chlorine and hydrogen.
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