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Energy Transfer & Work Done Simplified Revision Notes

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1.1.2 Energy Transfer & Work Done

  • Energy can be transferred between energy stores in one of the following ways: Mechanical Work – when a force moves an object at a distance.

Heating – when energy is transferred to a colder object from a hotter object.

Electrical Work – when energy is transferred by a moving charge due to a potential difference.

Radiation – when energy is transferred as an electromagnetic wave e.g. gamma-rays or UV radiation

Examples:

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A ball rolling and hitting a wall The system is moving the ball

  • When it hits the wall, (some of) the kinetic energy is transferred as sound
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Vehicle slowing down

  • System is vehicle moving
  • When it slows down, kinetic transfers to thermal due to friction between wheels and brakes

Energy Transfers

Pendulum - The Law of Conservation of Energy

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Energy cannot be created or destroyed; it can only be transferred, stored, or dissipated.

System Definition

  • System: An object or a group of objects.

    • Example: Pendulum
    • Components:
    • Fixed point
    • String
    • Mass
    • Air particles image
  • Closed System: No energy can enter or leave.

Energy Transfer in a Pendulum

  • Pendulum Motion:
    • At the highest points: Maximum Gravitational Potential Energy (GPE)
    • At the lowest point: Maximum Kinetic Energy (KE)

Friction in the Pendulum

  • Sources of Friction:

  • Friction in the fixed point

  • Friction as the pendulum passes through air particles

    image
  • Effect of Friction:

    • Energy transferred to thermal energy
    • Fixed point and air around the pendulum become warmer
    • Thermal energy is less useful
    • Energy dissipation causes the pendulum to swing with less energy and eventually stop

Reducing Unwanted Energy Transfers

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Method:

  • Reduce friction by using a lubricant (e.g., oil on the fixed point)
  • Remove air particles from around the pendulum

Bungee Jumper

Energy Transfers During a Bungee Jump

  • At the start of the jump:
  • All energy in the system is the store of gravitational potential energy (GPE). image
image
  • As the jumper falls:

  • Energy is transferred from the GPE store to the kinetic energy (KE) store.

  • When the bungee rope just starts to tighten:

  • The kinetic energy store is now at its maximum.

image image

Maximum Kinetic Energy

  • When the rope is fully extended:
  • The KE store is zero.
  • The jumper is not moving.
  • All energy has been transferred to the elastic potential energy (EPE) store.

Elastic Potential Energy

  • As the rope recoils:
  • Energy is transferred from the EPE store back to the KE store.
  • During the ascent:
  • Energy transfers from the KE store back to the GPE store.
  • At the top of the ascent:
  • All of the energy is now in the GPE store. image

Bungee Jump

Energy Dissipation

  • Observation: The jumper never returns back to its original position.

Reasons for Energy Dissipation

  • Energy is dissipated as thermal energy due to:
    • Friction with air particles
    • Stretching effects in the bungee rope, which is not fully elastic

Work Done by a Force

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Definition

  • Work is done whenever energy is transferred from one store to another.
  • Mechanical work involves using a force to move an object.

Formula

Work done (J)=Force (N)×Distance (m)\text{Work done (J)} = \text{Force (N)} \times \text{Distance (m)}

Example

lightbulbExample

Example

  • Scenario: The driver applies the brakes, and the car comes to a stop.
  • Moving car → Kinetic energy store
  • Speed: 20 m/s
image
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Process:

  • When the driver presses the brakes, the brake presses against the wheel.
  • This creates friction between the brake and the wheel.
  • The kinetic energy stored in the car is transferred to the thermal energy stored in the brakes.
  • The temperature of the brakes increases, and the car slows down and stops.
Kinetic energy store of car→Thermal energy store of brakes\text{Kinetic energy store of car} \rightarrow \text{Thermal energy store of brakes}
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Calculation Example

  • Question: During braking, a force of 2000 N is applied to the brakes of a car. The car takes 20 m to come to a stop. Calculate the work done.
2000 N×20 m=40,000 J40 kJ2000 \, \text{N} \times 20 \, \text{m} = 40,000 \, \text{J}\\ 40 \, \text{kJ}
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