Photo AI

Last Updated Sep 26, 2025

Volume Simplified Revision Notes

Revision notes with simplified explanations to understand Volume quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

307+ students studying

Volume

What is a Prism?

Definition:

A prism is a 3D object where the cross-section (the shape you see if you cut straight through it) remains the same along the entire length of the object.

In simpler terms, if you were to slice the prism perpendicular to its length, every slice would look exactly the same.

infoNote

Examples of Prisms:

  • A cuboid (a box shape) is a prism because every cross-section parallel to its base is a rectangle of the same size.

  • A cylinder is also a prism because every cross-section parallel to its circular base is a circle of the same size. Non-Examples:

  • A pyramid is not a prism because as you move from the base to the apex, the cross-section changes size.

  • A cone is also not a prism for the same reason.


Working Out the Volume of a Prism

Formula:

VolumeofaPrism=AreaofRepeatingFace×LengthVolume of a Prism=Area of Repeating Face×Length
  • The repeating face is the 2D2D shape that, when extended or extruded along the length, creates the 3D3D prism.
  • The length (or height, depending on the orientation of the prism) is how far the shape extends in the third dimension.
infoNote

Example 1: Volume of a Cuboid

Problem: Calculate the volume of a cuboid with a base measuring 8 cm by 5 cm and a height of 4 cm.


Solution:

  1. Step 1: Calculate the Area of the Repeating Face
  • The repeating face of this cuboid is a rectangle.
  • Dimensions of the rectangle: Base b=8cmb=8 cm, Height h=5cm.h=5 cm. Formula for the Area of a Rectangle:
Area=b×hArea=b×h

Substitute the values:

Area=8 cm×5 cm=40 cm2Area=8 \ cm×5 \ cm=40 \ cm^2

The area of the repeating face is 40 cm².


  1. Step 2: Multiply by the Length (or Height) of the Prism
  • The length of the cuboid is 4 cm. Formula for the Volume of the Prism:
Volume=AreaofRepeatingFace×LengthVolume=Area of Repeating Face×Length

Substitute the values:

Volume=40 cm2×4 cm=160 cm3Volume=40 \ cm^2×4 \ cm=160 \ cm^3

The volume of the cuboid is 160 cm³.


Volume of a Triangular Prism

Key Formula:

VolumeofaPrism=AreaofRepeatingFace(CrossSection)×LengthVolume of a Prism=Area of Repeating Face (Cross-Section)×Length
  • The repeating face or cross-section of a triangular prism is a triangle.
  • The length (or height) of the prism is the distance the triangular face is extruded along.
infoNote

Example 2: Triangular Prism

Problem: Calculate the volume of a triangular prism where the base of the triangular face is 6m, the height of the triangular face is 11m, and the length of the prism is 5m. Note that an additional measurement of 15m is given, but this is not needed for the volume calculation.


Solution:

  1. Step 1: Calculate the Area of the Repeating Face (Triangle)
  • Dimensions of the triangle:
  • Base b=6mb=6 m
  • Height h=11mh=11 m

Formula for the Area of a Triangle:

Area=b×h2Area=\frac{b×h}2

Substitute the values:

Area=6 m×11 m2=66 m22=33 m2Area=\frac{6 \ m×11 \ m}2=\frac{66 \ m^2}2=33 \ m^2

The area of the triangular face is 33 m².


  1. Step 2: Multiply by the Length of the Prism
  • The length of the prism is 5 m. Formula for the Volume of the Prism:
Volume=AreaofRepeatingFace×LengthVolume=Area of Repeating Face×Length

Substitute the values:

Volume=33 m2×5 m=165 m3Volume=33 \ m^2×5 \ m=165 \ m^3

The volume of the triangular prism is 165 m³.


infoNote

Example 3: Volume of a Cylinder

Problem: Calculate the volume of a cylinder with a radius of 3mm and a height of 6.2mm.


Solution:

  1. Step 1: Calculate the Area of the Repeating Face (Circle)
  • Given:
  • Radius r=3mmr=3 mm Formula for the Area of a Circle:
Area=π×r2Area=π×r^2

Substitute the values:

Area=π×32=π×928.274 mm2Area=π×3^2=π×9≈28.274 \ mm^2

The area of the circular face is approximately 28.274 mm².

Note: Keep this value in your calculator to maintain accuracy for the next calculation.


  1. Step 2: Multiply by the Height of the Cylinder
  • Given:
  • Height h=6.2mmh=6.2 mm Formula for the Volume of the Cylinder:
Volume=AreaofRepeatingFace×HeightVolume=Area of Repeating Face×Height

Substitute the values:

Volume=28.274 mm2×6.2 mm175.3 mm3Volume=28.274 \ mm^2×6.2 \ mm≈175.3 \ mm^3

The volume of the cylinder is approximately 175.3 mm³ (rounded to 1 decimal place).


infoNote

Example 4: Complicated Prism

Problem: Calculate the volume of a prism where the cross-sectional face is a rectangle with a circular hole in it. The rectangle has a base of 5m, a height of 7m, and the circular hole has a radius of 1.5m. The length of the prism is 3m.


Solution:

  1. Step 1: Calculate the Area of the Complete Rectangle (Ignoring the Hole)
  • Dimensions of the rectangle:
  • Base b=5mb=5 m
  • Height h=7mh=7 m Formula for the Area of a Rectangle:
Area=b×hArea=b×h

Substitute the values:

Area=5 m×7 m=35 m2Area=5 \ m×7 \ m=35 \ m^2
  1. Step 2: Calculate the Area of the Circular Hole
  • Radius of the circle: r=1.5mr=1.5 m Formula for the Area of a Circle:
Area=π×r2Area=π×r^2

Substitute the values:

Area=π×(1.5 m)2=π×2.25 m27.068 m2Area=π×(1.5 \ m)^2=π×2.25 \ m^2≈7.068 \ m^2
  1. Step 3: Subtract the Area of the Circular Hole from the Area of the Rectangle
  • Area of Repeating Face:
AreaofRepeatingFace=AreaofRectangleAreaofCircleArea of Repeating Face=Area of Rectangle−Area of Circle

Substitute the values:

Area of Repeating Face=35 m27.068 m2=27.931 m2Area\ of\ Repeating\ Face=35\ m^2−7.068 \ m^2=27.931 \ m^2
  1. Step 4: Multiply by the Length of the Prism
  • Length of the prism: 3 m Formula for the Volume of the Prism:
Volume=AreaofRepeatingFace×LengthVolume=Area of Repeating Face×Length

Substitute the values:

Volume=27.931 m2×3 m=83.793 m3Volume=27.931 \ m^2×3 \ m=83.793 \ m^3

Round to one decimal place:

Volume:success[83.8m3]Volume≈:success[83.8 m³]

Volume of Pointed Shapes

Key Formula:

Volume of a Pointy Shape=Area of Base×Height3\text{Volume of a Pointy Shape}=\frac{\text{Area of Base}×Height}3
  • The area of the base is the area of the flat face (usually a circle for cones or a polygon for pyramids).
  • The height is the perpendicular distance from the base to the point (the apex) of the shape.
image
infoNote

Example 4: Volume of a Cone

Problem: Calculate the volume of a cone with a base radius of 90 m and a height of 50m.


Solution:

  1. Step 1: Calculate the Area of the Base (Circle)
  • Given:
  • Radius r=90mr=90 m

Formula for the Area of a Circle:

Area=π×r2Area=π×r^2

Substitute the values:

Area=π×(90 m)2=π×8100 m225,446.9 m2Area=π×(90 \ m)^2=π×8100 \ m^2≈25,446.9 \ m^2

The area of the circular base is approximately 25,446.9 m².


  1. Step 2: Use the Volume Formula for a Cone
  • Height of the cone: 50 m Formula for the Volume of a Cone:
Volume=Area of Base×Height3Volume=\frac{Area\ of\ Base×Height}3

Substitute the values:

                    $Volume=\frac{25,446.9\  m^2×50 \ m}3=\frac{1,272,345 \ m^3}3≈424,115 \ m^3$

Round to the nearest whole number:

Volume:success[424,115m3]Volume≈:success[424,115 m³]

Volume of a Sphere

Key Formula:

Volume of a Sphere=43×π×r3\frac{4}3×π×r^3

  • rr is the radius of the sphere.
  • ππ (pi) is approximately 3.14159.
image
infoNote

Example 5: Volume of a Sphere

Problem: Calculate the volume of a sphere with a radius of 12 km.


Solution:

  1. Step 1: Write Down the Formula
Volume of a Sphere=43×π×r3Volume\ of\ a\ Sphere=\frac{4}3×π×r^3
  1. Step 2: Substitute the Radius into the Formula
  • Given: r=12kmr=12 km
  • Substitute the value of rr into the formula:
Volume=43×π×(12)3Volume=\frac{4}3×π×(12)^3
  1. Step 3: Calculate the Cube of the Radius
  • Calculate 12312^3:
123=12×12×12=1,728 km312^3=12×12×12=1,728 \ km^3
  1. Step 4: Multiply by ππ and Then by 43\frac{4}3
  • Multiply by ππ:
π×1,7283.14159×1,728=5,429.63 km3π×1,728≈3.14159×1,728=5,429.63 \ km^3
  • Now, multiply by 43\frac{4}3:
Volume=43×5,429.637,238.29 km3Volume=\frac{4}3×5,429.63≈7,238.29 \ km^3
  1. Step 5: Final Answer
  • The volume of the sphere is approximately 7,238.29 km³.

Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master Volume

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

20 flashcards

Flashcards on Volume

Revise key concepts with interactive flashcards.

Try Maths Flashcards

2 quizzes

Quizzes on Volume

Test your knowledge with fun and engaging quizzes.

Try Maths Quizzes

28 questions

Exam questions on Volume

Boost your confidence with real exam questions.

Try Maths Questions

2 exams created

Exam Builder on Volume

Create custom exams across topics for better practice!

Try Maths exam builder

68 papers

Past Papers on Volume

Practice past papers to reinforce exam experience.

Try Maths Past Papers

Other Revision Notes related to Volume you should explore

Discover More Revision Notes Related to Volume to Deepen Your Understanding and Improve Your Mastery

Load more notes

Join 500,000+ GCSE students using SimpleStudy...

Join Thousands of GCSE Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered