Limonene vs Vanillin Simplified Revision Notes for Scottish Highers Chemistry
Revision notes with simplified explanations to understand Limonene vs Vanillin quickly and effectively.
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Limonene vs Vanillin
Limonene vs Vanillin
Limonene:
Limonene is a chemical compound composed of hydrogen and carbon atoms only.
It lacks oxygen-hydrogen bonds in its structure.
Limonene is non-polar in nature, meaning it has a fairly even distribution of charge throughout its molecule.
The intermolecular forces between limonene molecules are primarily weak London Dispersion Forces (LDFs).
Due to the weak forces, it requires very little energy to break these LDFs.
Consequently, limonene has a low boiling point, around 176°C.
It is highly volatile, meaning it easily transitions from a liquid to a gas at relatively low temperatures.
Vanillin:
Vanillin, on the other hand, contains oxygen atoms bonded to hydrogen.
This oxygen-hydrogen bonding imparts polarity to the molecule, making it very polar.
The intermolecular forces between vanillin molecules are predominantly strong Hydrogen Bonds (H Bonds).
These H Bonds are much stronger than London Dispersion Forces.
Consequently, it takes significantly more energy to break the H Bonds in vanillin.
This results in a higher boiling point for vanillin, approximately 285°C.
Vanillin is much less volatile compared to limonene due to its stronger intermolecular forces.
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Summary:
Limonene is a non-polar compound composed of carbon and hydrogen, with weak London Dispersion Forces between its molecules. It has a low boiling point and is highly volatile.
Vanillin, in contrast, is a polar compound containing oxygen-hydrogen bonds, leading to strong Hydrogen Bonds between its molecules. It has a higher boiling point and is less volatile compared to limonene.
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