Moles and Solutions

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Moles and Solutions

Using Molar Ratios in Solutions

The molar ratio of a chemical reaction is also applicable to reactions involving solutions.

Calculating Mass or Moles

To calculate the mass or number of moles of a reactant or product in a solution, you can use a formula triangle.

Example: Sodium Sulfate Formation

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Let's consider an example: What mass of sodium sulfate is formed when 250 cm³ of 0.1 mol L⁻¹ sodium hydroxide is neutralised by an excess of sulfuric acid?

Since there is an excess of acid, sodium hydroxide controls the product's amount.
Using the formula n = c x v, where n represents the number of moles, c is the concentration, and v is the volume, we can calculate the moles of sodium hydroxide: 0.1 x 0.25 = 0.025 moles.
The molar ratio from the balanced equation is necessary to determine how many moles of sodium sulfate will form.
Finally, the number of moles of sodium sulfate must be converted into its mass.

Conclusion

Understanding the use of molar ratios in solutions is crucial for accurately calculating the mass or moles of reactants and products in chemical reactions involving solutions. It allows chemists to make precise measurements and predictions in solution chemistry.

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