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Straight Line Simplified Revision Notes

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Co-Ordinate Geometry: The Line

Co-Ordinate Geometry Diagram

  • Distance between two points: |PQ| = √(x₂-x₁)² + (y₂-y₁)²

  • Midpoint of a line segment: (x₁+x₂/2, y₁+y₂/2)

Slope of a line

  • With two points (x,y₁) and (x₂,y₂) slope = m = y₂-y₁/x₂-x₁
  • In form y=mx+c slope = m
  • In form ax + by + c = 0 slope = -a/b

Equation of a line formula: y - y₁ = m (x-x₁)

  • a∥b ⟺ m₁=m₂ (parallel lines equal slopes)
  • a⊥b ⟺ m₁ m₂ = -1

Derivation of the Divisor of Line Segment

  • (x₁,y₁) (x₂,y₂) and R(x,y) are three points
  • R divides line segment created by other two points internally in the ratio a

R = (bx₁+ax₂/b+a, by₁+ay₂/b+a)

  • Note: If ratio was 1:1 we are talking about midpoint

Co-Ordinate Geometry: The Line

Equation of line

  • Formula above or y=mx+c (m = slope, c = y - intercept)
  • Parallel lines have equal slopes so x and y coefficients are in same ratio
  • Line parallel to ax+by+c = 0 is ax + by + d = 0 (where d ∈R)
  • Perpendicular lines slopes multiply to give -1
  • Line perpendicular to ax + by + c = 0 is bx - ay + d = 0 (where d ∈R)

Area of Triangle

  • To use following formula one vertex must be (0,0)
  • Let other vertex be (x₁, y₁), (x₂, y₂)

12x1y2x2y1\frac{1}{2} |x_1y_2 - x_2y_1|

  • If no vertex at (0,0) - translate one point to (0,0) and apply translation to the other two points.

Perpendicular Distance from a Point to a Line

Perpendicular Distance Formula

  • Perpendicular distance from point to line is the shortest distance.
  • Distance from point (x₁, y₁) to line ax + by + c = 0 :

d=ax1+by1+ca2+b2d = \frac{|ax_1+by_1+c|}{\sqrt{a^2+b^2}}

  • Equation of line must be in form ax + by + c = 0

Co-Ordinate Geometry: The Line

Angle of inclination and angle between two lines

  • Angle of inclination - anti - clockwise angle formed between a line and the positive sense of the x-axis
  • Slope and angle m = tan α
  • Horizontal lines - slope = 0, angle of inclination
  • Vertical lines have angle of inclination of 90°, slope is not defined if two lines p and q have slopes m1m_1 and m2m_2 respectively, and θ is the angle between them, then :

tanθ=±m1m21+m1m2\tan \theta = \pm \frac{m_1-m_2}{1+m_1m_2}

tanθ=m1m21+m1m2 acute angle\tan \theta = \left|\frac{m_1-m_2}{1+m_1m_2}\right| \text{ acute angle}

Can also be used to find the slope of a line if is known and one slope is known

Angle of inclination diagram

Find m1m_1 using formula.

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