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Example-Conservation of Kinetic Energy Simplified Revision Notes

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Conservation of Kinetic Energy Example

Scenario

  • A red snooker ball and a blue snooker ball, each with a mass of 160 g, are involved in a collision.
  • The red ball is initially moving from left to right at 0.28 m/s, while the blue ball is moving from right to left at 0.12 m/s.
  • After the collision, the blue ball moves from left to right at 0.18 m/s.

diagram

Calculate the velocity of the red ball after the collision.

  • Total momentum before the collision is equal to the total momentum after the collision.
  • Using the formula for momentum (p = mv), we have:
  • Total initial momentum = Total final momentum
  • (0.160 kg Ă— 0.28 m/s) + (0.160 kg Ă— (-0.12 m/s)) = (0.160 kg Ă— V)
  • (0.0448 kg m/s) - (0.0192 kg m/s) = (0.160 kg Ă— V)
  • (0.0256 kg m/s) = (0.160 kg Ă— V)
  • V = (0.0256 kg m/s) / (0.160 kg)
  • V = -0.16 m/s
  • The velocity of the red ball after the collision is approximately -0.16 m/s. The negative sign indicates that the direction is from right to left.

Use kinetic energy to determine whether the collision was elastic

  • To determine if the collision is elastic or not, we need to calculate the kinetic energy before and after the collision.
  • The equation for kinetic energy is KE = ½mv², where KE is kinetic energy, m is mass, and v is velocity.

Kinetic Energy Before the Collision

  • For the red ball: KE_red = ½ Ă— 0.160 kg Ă— (0.28 m/s)² = 0.006272 J
  • For the blue ball: KE_blue = ½ Ă— 0.160 kg Ă— (-0.12 m/s)² = 0.0009216 J
  • Total kinetic energy before the collision: KE_initial = KE_red + KE_blue = 0.006272 J + 0.0009216 J = 0.0071936 J

Conservation of Kinetic Energy Example

diagram

Kinetic Energy After the Collision

  • For the red ball (with velocity -0.16 m/s): KE_red_after = ½ Ă— 0.160 kg Ă— (-0.16 m/s)² = 0.002048 J
  • For the blue ball (with velocity 0.18 m/s): KE_blue_after = ½ Ă— 0.160 kg Ă— (0.18 m/s)² = 0.002304 J
  • Total kinetic energy after the collision: KE_final = KE_red_after + KE_blue_after = 0.002048 J + 0.002304 J = 0.004352 J

Comparison of Kinetic Energies

  • Total kinetic energy lost during the collision: ΔKE = KE_initial - KE_final = 0.0071936 J - 0.004352 J = 0.0028416 J
  • The collision is inelastic because kinetic energy is not conserved. In this case, 0.0028416 J of energy is lost during the collision.

Summary

  • The velocity of the red ball after the collision is approximately -0.16 m/s.
  • The collision is determined to be inelastic because there is a loss of kinetic energy, with 0.0028416 J of energy being lost during the collision.
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