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Examine the table above showing the mean monthly temperature and precipitation levels in Mullingar in 2012 - Junior Cycle Geography - Question 6 - 2013

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Examine the table above showing the mean monthly temperature and precipitation levels in Mullingar in 2012. Circle the correct answer in each of the following state... show full transcript

Worked Solution & Example Answer:Examine the table above showing the mean monthly temperature and precipitation levels in Mullingar in 2012 - Junior Cycle Geography - Question 6 - 2013

Step 1

(i) The lowest precipitation level recorded was 15.4 mm / 254.4 mm.

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Answer

To determine the lowest precipitation level, we refer to the precipitation data in the table. The monthly precipitation levels are: 97.4 mm (Jan), 42.4 mm (Feb), 74.5 mm (Mar), 54.1 mm (Apr), 75.1 mm (May), 15.4 mm (Jun), 129.1 mm (Jul), 68.5 mm (Aug), 80.0 mm (Sep), 5.0 mm (Oct), 2.9 mm (Nov), and 25.4 mm (Dec). From this, it is clear that the lowest recorded precipitation level is 15.4 mm, which supports the answer being correct.

Step 2

(ii) The lowest temperature recorded was 5.5 °C / 2.9 °C.

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Answer

For the lowest temperature, we examine the temperature data provided: 5.8 °C (Jan), 6.6 °C (Feb), 6.7 °C (Mar), 7.5 °C (Apr), 10.5 °C (May), 13.0 °C (Jun), 15.3 °C (Jul), 15.4 °C (Aug), 8.0 °C (Sep), 5.5 °C (Oct), 2.9 °C (Nov), and 5.9 °C (Dec). The two lowest temperatures here are 5.5 °C and 2.9 °C, confirming that 2.9 °C is the lowest recorded temperature.

Step 3

(iii) The mean temperature for June, July and August was 42.3 °C / 14.1 °C.

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Answer

To find the mean temperature for June, July, and August, we add the temperatures for these months: 13.0 °C (Jun) + 15.3 °C (Jul) + 15.4 °C (Aug) = 43.7 °C. To find the mean, we divide this sum by the number of months, 3:

extMean=43.7°C3=14.5667°C. ext{Mean} = \frac{43.7 °C}{3} = 14.5667 °C. This rounds to approximately 14.1 °C, affirming that the statement about the mean temperature is correct.

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