Amie and Joe are asked to pick values for the numbers $p$, $q$, and $r$ so that the following is true for all $a \, ext{in} \, ext{R} :$
$$p^a \times q^a \times r^a = q^{12}$$
(i) Amie picked three values that were all the same, so $p = q = r$ - Junior Cycle Mathematics - Question 7 - 2022
Question 7
Amie and Joe are asked to pick values for the numbers $p$, $q$, and $r$ so that the following is true for all $a \, ext{in} \, ext{R} :$
$$p^a \times q^a \times ... show full transcript
Worked Solution & Example Answer:Amie and Joe are asked to pick values for the numbers $p$, $q$, and $r$ so that the following is true for all $a \, ext{in} \, ext{R} :$
$$p^a \times q^a \times r^a = q^{12}$$
(i) Amie picked three values that were all the same, so $p = q = r$ - Junior Cycle Mathematics - Question 7 - 2022
Step 1
Amie picked three values that were all the same, so $p = q = r$.
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Answer
Since Amie chose all the same values for p, q, and r, we can write:
p = q = r = 4\
ext{(this satisfies } p^a \times q^a \times r^a = r^{12})
\end{align*}$$
Step 2
Joe picked three values that were all different.
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Answer
For Joe's case, we need three different values that add up to 12. One example could be:
p = 0, \
q = -1.5, \
r = 13.5\
ext{(these values are all different and sum to 12)}\
\end{align*}$$
Other combinations could also work, such as $p = 3$, $q = 4$, $r = 5$.
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