Work out the value of 3p − 4t², when p = 6 and t = 5 - Junior Cycle Mathematics - Question 5 - 2023

Question 5

Work out the value of 3p − 4t², when p = 6 and t = 5.
Multiply out and simplify (2x − 3)(4 − 5x + x²).
Factorise fully 10de − df − 5ef + 2d².
Worked Solution & Example Answer:Work out the value of 3p − 4t², when p = 6 and t = 5 - Junior Cycle Mathematics - Question 5 - 2023
Work out the value of 3p − 4t², when p = 6 and t = 5.

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To calculate the value of the expression, substitute the given values of p and t:
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Substitute p = 6 and t = 5 into the expression:
3(6)−4(5)2
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Carry out the calculations:
18−4(25)
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Now calculate:
18−100=−82
Thus, the answer is -82.
Multiply out and simplify (2x − 3)(4 − 5x + x²).

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To multiply out and simplify the expression, use the distributive property:
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Start with the given expression:
(2x−3)(4−5x+x2)
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Distribute (2x) to each term in the second parentheses:
2x(4)−2x(5x)+2x(x2)=8x−10x2+2x3
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Now distribute (-3) to each term:
−3(4)+3(5x)−3(x2)=−12+15x−3x2
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Combine all terms:
2x3−10x2+15x−12
The simplified expression is:
2x3−10x2+15x−12
Factorise fully 10de − df − 5ef + 2d².

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To factorise the expression, identify and factor out the common factors:
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Start with the expression:
10de−df−5ef+2d2
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Group terms to find common factors:
(10de+2d2)+(−df−5ef)
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Factor each group:
2d(5e+d)−f(d+5e)
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Notice the common factor (d+5e):
⇒(d+5e)(2d−f)
Thus, the fully factorised form is:
(d+5e)(2d−f)
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