Solve the equation $5x - 10 = 3x + 2$.
John says that $x = 4$ is a solution of $x^2 - 2x - 8 = 0$. Show that John is correct.
Solve the simultaneous equations:
$$x... show full transcript
Worked Solution & Example Answer:Solve the equation $5x - 10 = 3x + 2$ - Junior Cycle Mathematics - Question 11 - 2015
Step 1
Solve the equation $5x - 10 = 3x + 2$.
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Answer
To solve the equation, we first rearrange it:
5x−10=3x+2
Subtracting 3x from both sides gives:
5x−3x−10=2
This simplifies to:
2x−10=2
Now, we add 10 to both sides:
2x=12
Finally, dividing both sides by 2 yields:
x = 6.$$
Step 2
Show that John is correct.
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Answer
To verify John's statement, we substitute x=4 into the equation:
42−2(4)−8=0.
Calculating the left-hand side:
16−8−8=0,
which simplifies to:
0=0.
Thus, John is correct since the equation holds true.
Step 3
Solve the simultaneous equations:
$$x + y = 11$$
$$x - y = -5.$$
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Answer
We can start by expressing x from the second equation:
x=y−5.
Substituting this into the first equation results in:
(y−5)+y=11.
This simplifies to:
2y−5=11.
Adding 5 to both sides gives:
2y=16,
which leads to:
y=8.
Now substituting y back into x=y−5 gives:
x=8−5=3.
Thus, the solution of the simultaneous equations is x=3 and y=8.
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