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(a) Write the following as a single fraction in its simplest form: \( \frac{2}{3} + \frac{5}{7} \) (b) Solve the following equation in k: \( 4k - 7 = 41 \) - Junior Cycle Mathematics - Question 10 - 2022

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Question 10

(a)-Write-the-following-as-a-single-fraction-in-its-simplest-form:--\(-\frac{2}{3}-+-\frac{5}{7}-\)--(b)-Solve-the-following-equation-in-k:--\(-4k---7-=-41-\)-Junior Cycle Mathematics-Question 10-2022.png

(a) Write the following as a single fraction in its simplest form: \( \frac{2}{3} + \frac{5}{7} \) (b) Solve the following equation in k: \( 4k - 7 = 41 \)

Worked Solution & Example Answer:(a) Write the following as a single fraction in its simplest form: \( \frac{2}{3} + \frac{5}{7} \) (b) Solve the following equation in k: \( 4k - 7 = 41 \) - Junior Cycle Mathematics - Question 10 - 2022

Step 1

Write the following as a single fraction in its simplest form:

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Answer

To combine ( \frac{2}{3} ) and ( \frac{5}{7} ), we first find a common denominator. The least common multiple of 3 and 7 is 21.

Convert each fraction:

( \frac{2}{3} = \frac{2 \cdot 7}{3 \cdot 7} = \frac{14}{21} )

( \frac{5}{7} = \frac{5 \cdot 3}{7 \cdot 3} = \frac{15}{21} )

Now, add the two fractions:

( \frac{14}{21} + \frac{15}{21} = \frac{14 + 15}{21} = \frac{29}{21} )

Thus, the single fraction in its simplest form is ( \frac{29}{21} ).

Step 2

Solve the following equation in k:

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Answer

To solve the equation ( 4k - 7 = 41 ), first add 7 to both sides:

( 4k - 7 + 7 = 41 + 7 )

This simplifies to:

( 4k = 48 )

Next, divide both sides by 4:

( k = \frac{48}{4} )

Thus, ( k = 12 ).

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