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Joshua estimates that an airbed is roughly in the shape of a rectangular solid - Junior Cycle Mathematics - Question 3 - 2022

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Joshua estimates that an airbed is roughly in the shape of a rectangular solid. The dimensions of the airbed are 180 cm by 80 cm by 20 cm. (a) Use Joshua’s values t... show full transcript

Worked Solution & Example Answer:Joshua estimates that an airbed is roughly in the shape of a rectangular solid - Junior Cycle Mathematics - Question 3 - 2022

Step 1

Use Joshua’s values to show that the volume of the airbed is 288 000 cm³.

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Answer

To calculate the volume of the airbed, we use the formula for the volume of a rectangular solid:

V=limeswimeshV = l imes w imes h

Where:

  • l=180cml = 180 \, \text{cm} (length)
  • w=80cmw = 80 \, \text{cm} (width)
  • h=20cmh = 20 \, \text{cm} (height)

Substituting these values into the formula:

V=180imes80imes20=288000cm3V = 180 imes 80 imes 20 = 288000 \, \text{cm}^3

Thus, the volume of the airbed is indeed 288 000 cm³.

Step 2

Work out how many minutes it will take to fill the airbed with air, using this pump.

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Answer

The pump blows air at a rate of 800 cm³ per second. To determine how many seconds it will take to fill the airbed, we use the following equation:

Time (seconds)=VolumeRate\text{Time (seconds)} = \frac{\text{Volume}}{\text{Rate}}

Substituting in the values:

Time (seconds)=288000800=360 seconds\text{Time (seconds)} = \frac{288000}{800} = 360 \text{ seconds}

To convert seconds to minutes, we divide by 60:

Time (minutes)=36060=6 minutes\text{Time (minutes)} = \frac{360}{60} = 6 \text{ minutes}

Therefore, it will take 6 minutes to fill the airbed with air.

Step 3

At what time does Joshua go to bed?

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Answer

Joshua finishes pumping at 9:35 p.m. He goes to bed 45 minutes later. To find the time he goes to bed, we add 45 minutes to 9:35 p.m.:

9:35 p.m. + 0:45 = 10:20 p.m.

Thus, Joshua goes to bed at 10:20 p.m.

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